Question

我有一个像

这样的数组

//$ary, $ary contains some 80 entries, I'm showing only the first 10
Array
(
    [0] => Array
        (
            [December 2012] => 58
        )
    [1] => Array
        (
            [November 2012] => 84
        )
    [2] => Array
        (
            [December 2012] => 83
        )
    [3] => Array
        (
            [November 2012] => 72
        )
    [4] => Array
        (
            [November 2012] => 47
        )
    [5] => Array
        (
            [December 2012] => 93
        )
    [6] => Array
        (
            [November 2012] => 79
        )
    [7] => Array
        (
            [October 2012] => 70
        )
    [8] => Array
        (
            [November 2012] => 75
        )
    [9] => Array
        (
            [October 2012] => 59
        )
    [10] => Array
        (
            [December 2012] => 67
        )
)

我可以使用以下方式获得每月的总数：

foreach($ary as $array)
{   
    foreach($array as $month=>$cent)
    {

        if(isset($abc[$month])) // prevent index warning
        {           
            $abc[$month] += $cent;
           // tried using $abc[$month] = $abc[$month]/2 but wrong values were returned
        }
        else
        {
            $abc[$month] = $cent;
        }
    }
}

这导致

Array
(
    [December 2012] => 2195
    [November 2012] => 2159
    [October 2012] => 1631
)

但我无法找到找到每月平均值的方法。就我而言，有December 2012的31个实例，November 2012的31个实例和October 2012的25个实例。因此，我需要掌握这些31，31和25值，以便我可以将该月份除以该数字。

我认为必须在if(isset($abc[$month]))循环中完成一些事情才能捕获但到目前为止还没有成功。还有其他方法可以获得平均值吗？

PS：我无法对月份名称（十月，十一月，十二月）进行硬编码以进行比较。他们会定期更换。

Answer 1

$eachMonth = array();
foreach($ary as $array)
{   
   foreach($array as $month=>$cent)
  {

    $eachMonth[$month][] = $cent;

    if(isset($abc[$month])) // prevent index warning
    {           
        $abc[$month] += $cent
    }
    else
    {
        $abc[$month] = $cent;
    }
  }
}

然后每月你可以计算平均值：

foreach( $eachMonth as $month => $values)
{
   echo $month.' : '.$abc[$month] / count($values);

}

Answer 2

试试这个：

$your_array = array(array("December 2012" => 58),
               array("December 2012" => 58)
              );

$res    = array();            
foreach($your_array as $val){
  $res[key($val)][] = $val[key($val)];
}

foreach($res as $k=>&$v){
   $v    = array_sum($v)/count($v);
}

echo "<pre>";
print_r($res);

查找关联数组的相同键值的平均值

2 个答案: