我有一个表有员工部门的员工,员工和工资。我想要一个查询来列出部门明智的最高工资和雇员的工资名称。
我知道这很简单。我用Google搜索,但找到了这样的答案,其中只列出了部门和工资
SELECT dept, SUM (salary)
FROM employee
GROUP BY dept;
答案 0 :(得分:4)
SELECT e1.*
FROM employee e1
JOIN (SELECT dept, MAX(salary) FROM employee GROUP BY dept) e2 ON
e1.dept = e2.dept AND e1.salary = e2.salary
答案 1 :(得分:3)
SQL Server 2008支持Window Functions
,可帮助您获得所需内容。
WITH recordList
AS
(
SELECT dept, employeeName, salary,
DENSE_RANK() OVER (PARTITION BY dept ORDER BY salary DESC) rn
FROM employee
)
SELECT dept, employeeName, salary
FROM recordList
WHERE rn = 1
答案 2 :(得分:3)
SELECT e.*, d.deptname
FROM employee e
JOIN department d ON e.deptid = d.deptid
WHERE EXISTS (SELECT 1
FROM employee e_in
JOIN department d_in ON e_in.deptid = d_in.deptid
WHERE d_in.deptid = d.deptid
GROUP BY d_in.deptid
HAVING MAX(e_in.salary) = e.salary)
答案 3 :(得分:3)
这样就可以了。
SELECT E1.DEPT, E2.ENAME, E1.HIGHEST_SALARY
FROM
(SELECT DEPT, MAX(SALARY) HIGHEST_SALARY
FROM EMPLOYEE
GROUP BY DEPT) E1
INNER JOIN EMPLOYEE E2 ON E1.HIGHEST_SALARY = E2.SALARY
AND E1.DEPT = E2.DEPT
答案 4 :(得分:-1)
select * from (select salary,last_name,dense_rank()
over (order by salary desc)
sal_rank from employees) where sal_rank <=3;
全部......这是下面的输出:
SALARY LAST_NAME SAL_RANK
---------- ------------------------- ----------
24000 King 1
17000 Kochhar 2
17000 De Haan 2
14000 Russell 3