我有这个类来处理通过selectionSort
排序数组。 。 。我在主要功能中排序我的数组时遇到问题(附在底部)...调用selctionSort()
的正确方法是什么?
我的问题:“类型selectionSort(T[], int)
中的方法SortArray
不适用于参数(int[], int)
”...我正在尝试将我的int数组传递给函数,它一直给我这个错误。
/**
Class for sorting an array of Comparable objects from smallest to
largest.
*/
public class SortArray
{
/** Sorts the first n objects in an array into ascending order.
@param a an array of Comparable objects
@param n an integer > 0 */
public static <T extends Comparable<? super T>> void selectionSort(T[] a, int n)
{
for (int index = 0; index < n - 1; index++)
{
int indexOfNextSmallest = getIndexOfSmallest(a, index, n - 1);
swap(a, index, indexOfNextSmallest);
// Assertion: a[0] <= a[1] <= . . . <= a[index] <= all other a[i]
} // end for
} // end selectionSort
/** Finds the index of the smallest value in a portion of an array.
@param a an array of Comparable objects
@param first an integer >= 0 and < a.length that is the index of
the first array entry to consider
@param last an integer >= first and < a.length that is the index
of the last array entry to consider
@return the index of the smallest value among
a[first], a[first + 1], . . . , a[last] */
private static <T extends Comparable<? super T>>
int getIndexOfSmallest(T[] a, int first, int last)
{
T min = a[first];
int indexOfMin = first;
for (int index = first + 1; index <= last; index++)
{
if (a[index].compareTo(min) < 0)
{
min = a[index];
indexOfMin = index;
} // end if
// Assertion: min is the smallest of a[first] through a[index].
} // end for
return indexOfMin;
} // end getIndexOfSmallest
/** Swaps the array entries a[i] and a[j].
@param a an array of objects
@param i an integer >= 0 and < a.length
@param j an integer >= 0 and < a.length */
private static void swap(Object[] a, int i, int j)
{
Object temp = a[i];
a[i] = a[j];
a[j] = temp;
} // end swap
} // end SortArray
public static void main(String[] args) {
int[] anArray = {15, 8, 10, 2, 5}; // given array
System.out.println("Printing unsorted array...");
for(int i = 0; i < anArray.length; i++)
System.out.print(anArray[i] + " ");
SortArray.selectionSort(anArray, anArray.length);
System.out.println("\nPrinting sorted array...");
}
答案 0 :(得分:1)
您的方法需要一个对象数组而不是基元数组。所以int []不起作用,但Integer []会起作用。
public static void main(String[] args) {
// int[] anArray = {15, 8, 10, 2, 5}; // given array
Integer[] anArray = { 15, 8, 10, 2, 5 }; // given array
System.out.println("Printing unsorted array...");
for (int i = 0; i < anArray.length; i++)
System.out.print(anArray[i] + " ");
SortArray.selectionSort(anArray, anArray.length);
System.out.println("\nPrinting sorted array...");
for (int i = 0; i < anArray.length; i++)
System.out.print(anArray[i] + " ");
}
编辑:实际上,它需要的不仅仅是Object数组。他们还必须实现Comparable接口。
答案 1 :(得分:0)
仔细阅读你的声明:
public static <T extends Comparable<? super T>> void selectionSort(T[] a, int n)
T
必须是扩展Comparable
的类型。
当您使用它时:
SortArray.selectionSort(anArray, anArray.length);
第一个参数的类型为int[]
,而int
未满足T
的此要求。
您可以考虑传入int[]
,而不是传入Integer[]
。 Integer
本身实现Comparable
,您无需更改大量代码即可使用它进行切换。只需将anArray
的声明从int[]
更改为Integer[]
即可。