我需要以下SQL的帮助: -
UPDATE `mg_catalog_category_entity_varchar` AS t1 INNER JOIN `mg_catalog_category_entity`
AS t2 ON t1.`entity_id`= t2.`entity_id`
SET t1.`value` = CONCAT('US Sports Goods ', t1.`value`, ' | My Site Name')
WHERE t2.`path` LIKE '1/2642%' AND t2.`level` > 1 AND t1.`attribute_id` = 40
我的问题是,t1.value
语句中的CONCAT()
字段需要提取t1.value
WHERE t1.attribute_id = 35
,我正在努力弄清楚如何正确指定CONCAT()
声明。
答案 0 :(得分:0)
试试这个:
UPDATE `mg_catalog_category_entity_varchar` AS t1 INNER JOIN `mg_catalog_category_entity`
AS t2 ON t1.`entity_id`= t2.`entity_id`
SET t1.`value` = CONCAT('US Sports Goods ', (SELECT t3.`value` FROM `mg_catalog_category_entity_varchar` AS t3 WHERE t3.`attribute_id` = 35 LIMIT 1), ' | My Site Name')
WHERE t2.`path` LIKE '1/2642%' AND t2.`level` > 1 AND t1.`attribute_id` = 40
答案 1 :(得分:0)
试试这个:
UPDATE `mg_catalog_category_entity_varchar` AS t1
INNER JOIN `mg_catalog_category_entity` AS t2 ON t1.`entity_id`= t2.`entity_id`
INNER JOIN
(
SELECT *
FROM mg_catalog_category_entity_varchar
WHERE `attribute_id` = 35
) AS t12 ON t2.entity_id = t12.entity_id
SET t1.`value` = CONCAT('US Sports Goods ', t12.`value`, ' | My Site Name')
WHERE t2.`path` LIKE '1/2642%'
AND t2.`level` > 1
AND t1.`attribute_id` = 40