Bash here docs＆lt;＆lt; - 跳过领先的空白

Question

我可以这样做：

declare foo -r -d '' <<- 'EOF'
->-> Sopra la panca
->-> la capra campa
EOF

（其中->表示TAB）

然后将忽略前导标签。

<<-可以用来跳过/忽略前导space，而不仅仅是tab s？

Answer 1

引用 from Greg

In this form, all leading tab characters (not spaces!) will be removed. There is 
no provision for removing leading spaces, or leading tabs-and-spaces. (Recall the
syntactic restrictions of Makefiles, and you'll be OK.)