Question

我正在努力展示至少占其主管制作成果25％的员工。到目前为止，我有一个子查询代码可以显示主管本身，但我不知道如何“抓住”主管工资：

SELECT TOP (100) PERCENT firstname + ' ' + lastname        AS Employee, 
                         id, 
                         jobtitle                          AS [Job Title], 
                         Str(Round(salary / 12, 2), 12, 2) AS [Monthly Salary] 
FROM   employeetable 
WHERE  ( id IN (SELECT supervisor 
                 FROM   employeetable 
                 WHERE  ( supervisor IS NOT NULL )) ) 
ORDER  BY lastname, 
          firstname

Answer 1

- 首先，找到员工和主管

select emp.id,emp.Salary,Sup.SuperVisor,Sup.Salary
from employeetable emp
join employeetable Sup on emp.supervisor=Sup.id

现在添加where子句

where emp.Salary >= .25 * Sup.Salary

消除监督人员

and emp.id not in (select distinct supervisor from employeetable)

比较主管的薪水

1 个答案: