Postgresql查询速度很慢

时间:2013-03-20 22:20:02

标签: postgresql query-optimization database-performance

此查询运行速度非常慢。为什么?其他人都很好。我认为指数很好。

explain analyze 
select "e_inst"."si_id" as "c0" 
from "e_inst" as "e_inst" 
group by "e_inst"."si_id" 
order by "e_inst"."si_id" ASC NULLS LAST

查询计划:

Sort  (cost=12221.87..12221.90 rows=68 width=4) (actual time=1115.377..1115.433 rows=81 loops=1)
  Sort Key: si_id
  Sort Method: quicksort  Memory: 28kB
  ->  HashAggregate  (cost=12221.25..12221.45 rows=68 width=4) (actual time=1115.198..1115.261 rows=81 loops=1)
        ->  Seq Scan on e_inst  (cost=0.00..11920.07 rows=602357 width=4) (actual time=0.021..611.570 rows=602357 loops=1)
Total runtime: 1115.538 ms

创建表和索引:

CREATE TABLE e_inst (
    id integer NOT NULL,
    ip numeric,
    gu character varying,
    referrer character varying,
    proc integer,
    loke_id integer,
    top_id integer,
    si_id integer,
    kop integer,
    count integer,
    created integer,
    modified integer,
    timepop integer,
    count_active character varying,
    country character(3),
    info character varying
);

CREATE INDEX "topEnhance" ON e_inst USING btree (created, top_id);
CREATE INDEX "procEnhance" ON e_inst USING btree (created, proc);
CREATE INDEX "countryEnhance" ON e_install USING btree (created, country);
CREATE INDEX "createdE" ON e_inst USING btree (created);
ALTER TABLE e_inst CLUSTER ON "createdE";
CREATE INDEX "lokeE" ON e_inst USING btree (loke_id);
CREATE INDEX "lokeEnhance" ON e_inst USING btree (created, loke_id);
CREATE INDEX "siE" ON e_inst USING btree (si_id);
CREATE INDEX "siEnhance" ON e_inst USING btree (created, si_id);
CREATE INDEX "kopEnhance" ON e_inst USING btree (created, kop);

2 个答案:

答案 0 :(得分:3)

处理整个表的查询不会使用索引。

事实上,您正在检索并处理 600k记录。它在一秒钟内实现这一点实际上是令人印象深刻的。

现在在这种情况下,您试图从600k记录中提取出81个不同的值。你可能想要做的是构造一个递归查询,使其获取一行81次。这个可能更快,但无法保证。通常我会在返回的行数少得多的地方使用它们。不过这是一个例子:

WITH RECURSIVE sparse_scan AS (
    SELECT min(si_id) as si_id FROM e_inst
    UNION ALL
    SELECT min(si_id) as si_id
      FROM e_inst
      JOIN (select max(si_id) as last FROM sparse_scan) s
     WHERE s.last < si_id
)
SELECT si_id as c0 FROM sparse_scan;

请注意,这将使用81次索引扫描替换顺序扫描。

答案 1 :(得分:0)

升级到PostgreSQL 9.2。现在这只是一个索引扫描! 工作得很好,感谢a_horse_with_no_name谁建议我升级。