Question

我正在尝试在我的ajax保存功能中发送多个数据数组。

我可以像data:hardwarePayload一样单独执行每个数组，它会起作用。如果我做{hardware: hardwarePayload, service:servicePayload}我得到非常奇怪的JSON输出。看起来像是：

硬件=％5B％7B％22hardwareName％22％3A％221％22％2C％22hardwareQuantity％22％3A％22％22％2C％22hardwareBYOD％22％3A％22％22％7D％5D＆安培;服务= ％5B％7B％22serviceName％22％3A％223％22％2C％22serviceQuantity％22％3A％22％22％7D％5D

我真的需要两个阵列，一个硬件和一个服务，所以我可以单独抓取每个。

我的代码看起来像这样..

self.save = function (form) {
    var hardwareModel = [];
    var serviceModel = [];
    ko.utils.arrayForEach(self.services(), function (service) {
        serviceModel.push(ko.toJS(service));
    });
    ko.utils.arrayForEach(self.hardwares(), function (hardware) {
        hardwareModel.push(ko.toJS(hardware));
    }); 
  //allModel.push({accountId: ko.toJS(account)});
    var hardwarePayload = JSON.stringify(hardwareModel);
    var servicePayload = JSON.stringify(serviceModel);
  //alert(JSON.stringify(serviceModel) +JSON.stringify(allModel));
    $.ajax({
        url: '/orders/add',
        type: 'post',
        data: {hardware: hardwarePayload, service:servicePayload}, //            data:hardwarePayload,
        contentType: 'application/json',
        success: function (result) {
            alert(result);
        }
    });
};

Answer 1

你应该试试这个

var hardwarePayload = hardwareModel;
var servicePayload = serviceModel;

var postData = {'hardware': hardwarePayload, 'service':servicePayload};

var postData = JSON.stringify(postData);

alert(postData);

$.ajax({
    url: '/orders/add',
    type: 'post',
    data: postData,
    contentType: 'application/json',
    success: function (result) {
        alert(result);
    }
});

Answer 2

如果你不字符串你的数据，我认为你会更好：

$.ajax({
    url: '/orders/add',
    type: 'post',
    data: {hardware: hardwareModel, service:serviceModel}, //            data:hardwarePayload,
    contentType: 'application/json',
    success: function (result) {
        alert(result);
    }
});

（请注意，我使用不字符串化 hardwareModel 和 serviceModel ）

这样你就可以让jQuery处理请求的（json）数据。

JS AJAX发送多个数据数组

2 个答案: