Question

使用SQL Server 2008，我试图让其中一些列返回$ xxx，xxx.xx

这是我正在使用的查询（此查询然后一些更新只是为了计算数字并在结尾处选择##tempshow）

SELECT 
    CASE GROUPING(s.StoreID) WHEN 1 THEN '' ELSE s.StoreID END [StoreID],
    CASE GROUPING(p.VendorID) WHEN 1 THEN '' ELSE p.VendorID END [VendorID],
    SUM(d.Quantity) AS [UnitSold],
    CAST(SUM(d.amount * d.quantity) AS DECIMAL(18,2)) AS Amount, 
    CAST(SUM(d.Discount) AS DECIMAL(18,2)) AS Discount,
    CAST(SUM((d.Amount * d.Quantity - d.Discount)) AS DECIMAL(18,2)) AS ExtSold,
    CAST(SUM(d.Cost * d.Quantity) AS DECIMAL(18,2)) AS Cost,
    CAST(0 AS DECIMAL(18,2)) AS Profit,
    CAST(0 AS DECIMAL(18,2)) AS OnHand,
    CAST(0 AS DECIMAL(18,2)) AS OnHandRetail,
    CAST(0 AS DECIMAL(18,2)) AS OnHandCost,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedCost,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedRetail,
    CAST(0 AS DECIMAL(18,2)) AS ReceivedQty,
    CAST(0 AS DECIMAL(18,2)) AS Margin,
    CAST(0 AS DECIMAL(12,2)) AS TurnOver,
    CAST(0 AS INTEGER) AS OnOrder 
INTO
    ##tempshow
FROM 
    RPTrs s,
    RPTrsd d,
    RPIv i,
    RPProducts p
WHERE 
    s.ReceiptNO = d.ReceiptNO and 
    s.StoreID = d.StoreID and 
    i.UPC = d.UPC and 
    i.StoreID = d.StoreID and 
    p.ProductID = i.IVProduct and 
    s.StoreID = '01' and
    s.TRSDate > GETDATE()-20 and 
    p.Service = 0 
GROUP BY 
    GROUPING SETS((s.StoreID,p.VendorID),())

返回： enter image description here

我试过了

CAST(SUM(d.amount * d.quantity) AS MONEY) AS Amount,

和

SUM(CAST((d.amount * d.quantity) AS MONEY)) AS Amount,

预期输出（加上与此Amount列相同的其他列）：

  |StoreID | VendorID | UnitSold | Amount
---------------------------------------------
1 | 01     | 0000     | 0        | $0.00
2 | 01     | am       | 62       | $6,275.00
3 | 01     | AO       | 58       | $18,964.00
4 | 01     | payless  | 6        | $1,383.36
5 |        |          | 126      | $26,622.36

我需要Amount, Discount, ExtSold, Cost, Profit, OnHandRetail, OnHandCost, ReceivedCost, ReceivedRetail采用货币格式

Answer 1

这应该在表示层上完成，但是如果你需要在sql中这样做，你可以使用：

'$'+convert(varchar(50), CAST(amount as money), -1) amount

以下是一个例子：

;with cte (amount)
as
(
    select 123254578.00 union all
    select 99966.00 union all
    select 0.00 union all
    select 6275.00 union all 
    select 18964.00 union all 
    select 1383.36 union all
    select 26622.36
)
select '$'+convert(varchar(50), CAST(amount as money), -1) amount
from cte

见SQL Fiddle with Demo。这将返回：

|          AMOUNT |
-------------------
| $123,254,578.00 |
|      $99,966.00 |
|           $0.00 |
|       $6,275.00 |
|      $18,964.00 |
|       $1,383.36 |
|      $26,622.36 |

注意：这在SQL Server 2012中会更容易，因为您可以使用FORMAT()

;with cte (amount)
as
(
    select 123254578.00 union all
    select 99966.00 union all
    select 0.00 union all
    select 6275.00 union all 
    select 18964.00 union all 
    select 1383.36 union all
    select 26622.36
)
select '$'+FORMAT(amount,'#,0.0000') amount
from cte

请参阅SQL Fiddle with Demo

Answer 2

添加到bluefeet的答案，SQL 2012中提供的FORMAT功能可以这样完成：

SELECT FORMAT(12345.6789, 'C', 'en-us')

C表示货币，最后一个参数是文化。如果您希望您的应用程序是多语言的，那么文化很重要，因为它会处理诸如美元（或欧元）符号和千位分隔符之类的事情。例如：

SELECT 
FORMAT(12345.6789, 'C', 'en-us') as "USA", 
FORMAT(12345.6789, 'C', 'fr-ca') as "French Canada", 
FORMAT(12345.6789, 'C', 'fr-fr') as "French France",
FORMAT(12345.6789, 'C', 'hi-in') as "Hindi India"

会给出这个结果：

USA            French Canada        French France     Hindi India
-----------    -------------        --------------    --------------
$12,345.68     12 345,68 $          12 345,68 €       ₹ 12,345.68

TSQL将总和转换为Money

2 个答案: