Question

我正在尝试编写一个可变参数函数，它将专门提供最后一个参数。

    // we take em all as long as they are convertible to string
    template<typename... Args>
    void warn(Args... args, string s){
        vector<string> joinable{args..., s};
        SMDiagnostic w(TUName, SourceMgr::DK_Warning,
                util::join(joinable));
        w.print("CGD.so", errs());
    }

    template<typename... Args>
    void warn(Args... args, Value const * v){
        string buffer;
        raw_string_ostream os(buffer);
        v->print(os);
        warn(args..., os.str());
    }

    template<typename... Args>
    void warn(Args... args, CallInst const * ci){
        warn(args..., dyn_cast<Value>(ci));
    }

我尝试用

打电话给他们

warn(me, someCallInst);

但是clang给了我一个奇怪的错误

error: no matching member function for call to 'warn'
       warn("We found a function usage that is not a call!! Ignoring\n", inst);
       ^~~~
../llvm_opt_pass/cgd.cpp:1062:8: note: candidate function not viable: requires 1 argument, but 2 were provided
                void warn(Args... args, CallInst const * ci){
                     ^
../llvm_opt_pass/cgd.cpp:1054:8: note: candidate function not viable: requires 1 argument, but 2 were provided
                void warn(Args... args, Value const * v){
                     ^
../llvm_opt_pass/cgd.cpp:1046:8: note: candidate function not viable: requires 1 argument, but 2 were provided
                void warn(Args... args, string s){

我需要做些什么才能使用这样的可变参数模板？

Variadic模板与类型在结束

0 个答案: