我知道在使用流时我需要刷新它以便释放与流相关的任何资源,并且刷新流会获取尚未写入的任何缓冲数据,并立即将其写出来。
我有以下课程:
[XmlRoot("EventList")]
public class EventList
{
private List<BaseEvent> events_ = new List<BaseEvent>();
/// Default constructor. Required for serialization
public EventList() {}
[XmlElement(ElementName = "Event")]
public List<BaseEvent> Events
{
get
{
return events_;
}
set
{
events_ = value;
}
}
}
现在在我发送它作为对HTTPRequest的响应之前,我是否需要刷新它?如果是这样我怎么办?
我问,因为我有这里描述的问题: AJAX response - XmlHttp.responseXML is cut off
js客户端激活的方法是:
[WebMethod]
public EventsRequestResult GetEvents(string agentId, int delayedReturnMS)
// EventsRequestResult - return value of the GetEvents method of the EventsService.
public class EventsRequestResult
{
private EventList events_ = null;
/// <summary>
/// List of the events
/// </summary>
[XmlElement(ElementName = "Events")]
public EventList Events
{
get
{
return events_;
}
set
{
events_ = value;
}
}
/// Default constructor.
public EventsRequestResult(){}
/// <summary>
/// Constructor used in case of the failure.
/// </summary>
/// <param name="errorCode">Numeric error code</param>
/// <param name="errorDescription">Human readable error description</param>
public EventsRequestResult(RequestErrorCode errorCode, string errorDescription) : base(errorCode, errorDescription){}
/// <summary>
/// Constructor used in case of successful events request.
/// </summary>
/// <param name="events">List of the events</param>
public EventsRequestResult(EventList events) : base()
{
events_ = events;
}
}
答案 0 :(得分:0)
Marc在上面的评论中是正确的,但我认为你正在寻找的是像
using(var stream = theResponse.OutputStream)
{
var ser = new XmlSerializer(typeof(EventList));
return ser.Deserialize(stream) as EventList;
}
使用块中的 return
将关闭(并刷新)流。