Question

我在SQL Server中有这种数据

Person  StartDate                  EndDate                  Value
-----------------------------------------------------------------
38523   2013-01-10 22:00:00.000    2013-01-10 22:59:00.000  0.064
38523   2013-01-10 23:00:00.000    2013-01-10 23:59:00.000  0.065
38523   2013-01-12 00:00:00.000    2013-01-12 00:59:00.000  0.068
38523   2013-01-12 01:00:00.000    2013-01-12 01:59:00.000  0.069
38523   2013-01-12 02:00:00.000    2013-01-12 02:59:00.000  0.069
38523   2013-01-12 03:00:00.000    2013-01-12 03:59:00.000  0.069
38523   2013-01-31 23:00:00.000    2013-01-31 23:59:00.000  0.061
38523   2013-02-01 00:00:00.000    2013-02-01 00:59:00.000  0.064

我需要以这样一种方式进行分组，即每个月应将连续值组合在一起。如果在上一个结束日期和下一个开始日期之间存在超过1分钟的间隔，则应将其拆分为单独的组。

预期结果：

Person  StartDate                  EndDate                  Sum(Value)
----------------------------------------------------------------------
38523   2013-01-10 22:00:00.000    2013-01-10 23:59:00.000  0.129
38523   2013-01-12 00:00:00.000    2013-01-12 03:59:00.000  0.275
38523   2013-01-31 23:00:00.000    2013-01-31 23:59:00.000  0.061 (even though continuity exists, month was end hence separate record)
38523   2013-02-01 00:00:00.000    2013-02-01 00:59:00.000  0.064

任何帮助表示感谢。

Answer 1

SELECT 
    CAST(DATEPART(YEAR, DateCreated) as varchar(10)) + '/' 
        + CAST(DATEPART(MONTH, DateCreated) as varchar(10))
FROM [Reporting].[dbo].[Hmis_Forms]
GROUP BY 
    CAST(DATEPART(YEAR, DateCreated) as varchar(10)) + '/' 
        + CAST(DATEPART(MONTH, DateCreated) as varchar(10))

Answer 2

根据您的数据和预期结果，以下查询可以帮助您：

SELECT 
    Person, 
    MIN(StartDate) as StartDate, 
    MAX(EndDate) as EndDate, 
    SUM(Value)
FROM table
GROUP BY 
    Person, 
    CAST(StartDate as date)

Answer 3

我有类似的东西，也许这可以帮到你：

CREATE TABLE #Test2 
(
    Person int, 
    StartDate datetime, 
    EndDate datetime, 
    Value numeric (12, 3), 
    NextDate datetime
);


INSERT INTO #Test2(Person, StartDate, EndDate, Value, NextDate)
SELECT 
    Person, 
    StartDate, 
    EndDate, 
    Value, 
    (SELECT TOP 1 StartDate FROM Test WHERE StartDate > t.EndDate ORDER BY StartDate, EndDate)  
FROM Test t



SELECT 
    MAX(StartDate) ,
    MAX(EndDate) ,
    SUM(Value)


FROM #Test2
GROUP BY 
    DATEDIFF(MINUTE, NextDate, EndDate)

ORDER BY 
    MAX(StartDate) ,
    MAX(EndDate)    
DROP TABLE #Test2

我做的是用新列创建临时表，保留下一个开始日期值。然后，我根据开始和结束日期的减法对值进行分组，以分钟为单位计算。

除了总和之外，我得到的结果与你的结果相同。

每月的日期范围分组

3 个答案: