Question

我目前有一个“日”对象列表。 Day的类定义包含两个字符串： -名称 -hours

我需要做的是在列表中查找具有相同小时数的所有日期，并将它们格式化为一个项目。

实施例。

Sunday 8am - 9pm
Monday 8am - 10pm
Tuesday 8am - 10pm
Wednesday 8am -10pm
Thursday 9am - 10pm
Friday 9am - 11pm
Saturday 8am - 11pm

因此，星期一和星期三的星期一都有相同的时间。我需要在原始文件中创建一个类似于：

的新列表

Sunday 8am - 9pm
Mon-Wed 8am -10 pm
...
...

使用LINQ有一种简单的方法吗？

Answer 1

这接近你想要的：

        IList<Day> days = new List<Day>();
        days.Add(new Day { Name = "Sunday", Hours = "8am - 9pm" });
        days.Add(new Day { Name = "Monday", Hours = "8am - 10pm" });
        days.Add(new Day { Name = "Tuesday", Hours = "8am - 10pm" });
        days.Add(new Day { Name = "Wednesday", Hours = "8am - 10pm" });
        days.Add(new Day { Name = "Thursday", Hours = "9am - 10pm" });
        days.Add(new Day { Name = "Friday", Hours = "9am - 11pm" });
        days.Add(new Day { Name = "Saturday", Hours = "8am - 11pm" });
        var grouped = days.GroupBy(d => d.Hours).ToList();
        StringBuilder sb = new StringBuilder();
        foreach (var group in grouped)
        {
            sb.AppendFormat("{0}: {1}\n", group.Key, group.Select(g => g.Name).Aggregate((list, nextday) => list + ", " + nextday));
        }
        var table = sb.ToString();

输出结果为：

上午8点 - 晚上9点：周日

早上8点 - 晚上10点：周一，周二，周三

上午9点 - 晚上10点：周四

上午9点 - 晚上11点：周五

上午8点 - 晚上11点：周六

Answer 2

使用GroupConsecutive扩展方法，您将在答案结束时找到该方法，您可以执行以下操作：

List<Day> days = new List<Day>
{
    new Day { Name = "Sunday", Hours= "8am - 9pm" },
    new Day { Name = "Monday", Hours= "8am - 10pm" },
    new Day { Name = "Tuesday", Hours= "8am - 10pm" },
    new Day { Name = "Wednesday", Hours= "8am - 10pm" },
    new Day { Name = "Thursday", Hours= "9am - 10pm" },
    new Day { Name = "Friday", Hours= "8am - 11pm" },
    new Day { Name = "Saturday", Hours= "8am - 11pm" },
};

var query = from g in days.GroupConsequtive(d => d.Hours)
            select new {
                Name = g.Count() == 1 ? g.First().Name :
                       String.Format("{0}-{1}", g.First().Name.Substring(0, 3), g.Last().Name.Substring(0, 3)),
                Hours = g.Key
            };

枚举结果：

foreach (var item in query)            
    Console.WriteLine("{0} {1}", item.Name, item.Hours);

输出：

Sunday 8am - 9pm
Mon-Wed 8am - 10pm
Thursday 9am - 10pm
Fri-Sat 8am - 11pm

连续分组的扩展方法：

public static class LazyExtensions
{
    public static IEnumerable<IGrouping<TKey, TElement>> GroupConsecutive<TKey, TElement>(
        this IEnumerable<TElement> source, Func<TElement, TKey> keySelector)
    {
        if (!source.Any())
            yield break;

        var comparer = Comparer<TKey>.Default;
        Grouping<TKey, TElement> group = null;

        foreach (var item in source)
        {
            var key = keySelector(item);

            if (group == null)
                group = new Grouping<TKey, TElement>(key);

            if (comparer.Compare(group.Key, key) != 0)
            {
                yield return group;
                group = new Grouping<TKey, TElement>(key);
            }

            group.Elements.Add(item);
        }

        yield return group;
    }

    private class Grouping<TKey, TElement> : IGrouping<TKey, TElement>
    {
        public Grouping(TKey key)
        {
            Key = key;
            Elements = new List<TElement>();
        }

        public List<TElement> Elements { get; private set; }
        public TKey Key { get; private set; }

        public IEnumerator<TElement> GetEnumerator()
        {
            return Elements.GetEnumerator();
        }

        IEnumerator IEnumerable.GetEnumerator()
        {
            return GetEnumerator();
        }
    }
}

它是如何工作的？它创建分组（自定义类，实现IGrouping接口），并将具有相同键值的连续元素添加到该组。如果新密钥值到达，则返回分组。因此，所有序列都按连续的键值分组。

Answer 3

List<Tuple<string,string>> days = new List<Tuple<string,string>>
(
    new Tuple<string,string>[]
    {
        new Tuple<string,string>( "Sunday", "8am - 9pm" ),
        new Tuple<string,string>( "Monday", "8am - 10pm" ),
        new Tuple<string,string>( "Tuesday", "8am - 10pm" ),
        new Tuple<string,string>( "Wednesday", "8am - 10pm" ),
        new Tuple<string,string>( "Thursday ", "9am - 10pm" ),
        new Tuple<string,string>( "Friday", "9am - 11pm" ),
        new Tuple<string,string>( "Saturday ", "8am - 11pm" )
    }
);

ILookup<string,string> table = days.ToLookup( k => k.Item2, v => v.Item1 );

table[ "8am - 9pm" ]; // Sunday
table[ "8am - 10pm" ]; // Monday, Tuesday, Wednesday

查询对象列表

3 个答案: