Question

今天早些时候，我可以使用以下代码从Google Patents中提取数据

import urllib2

url = 'http://www.google.com/search?tbo=p&q=ininventor:"John-Mudd"&hl=en&tbm=pts&source=lnt&tbs=ptso:us'
req = urllib2.Request(url, headers={'User-Agent' : "foobar"})

response = urllib2.urlopen(req)

现在，当我去运行它时，我得到以下503错误。我只用了30次这个代码（我试图获得30人名单所拥有的所有专利）。

HTTPError                                 Traceback (most recent call last)
<ipython-input-4-01f83e2c218f> in <module>()
----> 1 response = urllib2.urlopen(req)

C:\Python27\lib\urllib2.pyc in urlopen(url, data, timeout)
    124     if _opener is None:
    125         _opener = build_opener()
--> 126     return _opener.open(url, data, timeout)
    127 
    128 def install_opener(opener):

C:\Python27\lib\urllib2.pyc in open(self, fullurl, data, timeout)
    404         for processor in self.process_response.get(protocol, []):
    405             meth = getattr(processor, meth_name)
--> 406             response = meth(req, response)
    407 
    408         return response

C:\Python27\lib\urllib2.pyc in http_response(self, request, response)
    517         if not (200 <= code < 300):
    518             response = self.parent.error(
--> 519                 'http', request, response, code, msg, hdrs)
    520 
    521         return response

C:\Python27\lib\urllib2.pyc in error(self, proto, *args)
    436             http_err = 0
    437         args = (dict, proto, meth_name) + args
--> 438         result = self._call_chain(*args)
    439         if result:
    440             return result

C:\Python27\lib\urllib2.pyc in _call_chain(self, chain, kind, meth_name, *args)
    376             func = getattr(handler, meth_name)
    377 
--> 378             result = func(*args)
    379             if result is not None:
    380                 return result

C:\Python27\lib\urllib2.pyc in http_error_302(self, req, fp, code, msg, headers)
    623         fp.close()
    624 
--> 625         return self.parent.open(new, timeout=req.timeout)
    626 
    627     http_error_301 = http_error_303 = http_error_307 = http_error_302

C:\Python27\lib\urllib2.pyc in open(self, fullurl, data, timeout)
    404         for processor in self.process_response.get(protocol, []):
    405             meth = getattr(processor, meth_name)
--> 406             response = meth(req, response)
    407 
    408         return response

C:\Python27\lib\urllib2.pyc in http_response(self, request, response)
    517         if not (200 <= code < 300):
    518             response = self.parent.error(
--> 519                 'http', request, response, code, msg, hdrs)
    520 
    521         return response

C:\Python27\lib\urllib2.pyc in error(self, proto, *args)
    442         if http_err:
    443             args = (dict, 'default', 'http_error_default') + orig_args
--> 444             return self._call_chain(*args)
    445 
    446 # XXX probably also want an abstract factory that knows when it makes

C:\Python27\lib\urllib2.pyc in _call_chain(self, chain, kind, meth_name, *args)
    376             func = getattr(handler, meth_name)
    377 
--> 378             result = func(*args)
    379             if result is not None:
    380                 return result

C:\Python27\lib\urllib2.pyc in http_error_default(self, req, fp, code, msg, hdrs)
    525 class HTTPDefaultErrorHandler(BaseHandler):
    526     def http_error_default(self, req, fp, code, msg, hdrs):
--> 527         raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
    528 
    529 class HTTPRedirectHandler(BaseHandler):

HTTPError: HTTP Error 503: Service Unavailable

Answer 1

谷歌的TOS禁止自动查询，遗憾的是。几乎可以肯定地发现你“没有好处”。

来源：https://support.google.com/websearch/answer/86640?hl=en

Answer 2

在黑暗中猜测：

您是否在查看响应中是否有“Retry-After标头”。这是503的真实可能性。

From RFC 2616：

14.37重试 - 之后

Retry-After响应标头字段可与503一起使用（服务   不可用）响应以指示服务预期的时间   请求客户端无法访问。也可以使用该字段   使用任何3xx（重定向）响应来指示最小时间   在发出重定向的请求之前要求用户代理等待。该   该字段的值可以是HTTP日期或整数   响应时间后的秒数（十进制）。          Retry-After =“Retry-After”“：”（HTTP-date | delta-seconds）

其使用的两个例子是          Retry-After：1999年12月31日星期五23:59:59 GMT          Retry-After：120

在后一个例子中，延迟是2分钟。

尝试使用python访问Google Patents时出现503错误

2 个答案: