Question

我有以下代码：

import re

vars='"NAME=Product","TYPE=","VERSION=1.2","VISIBILITY=","SRC=","FOLDER=TRUE","Text=foo, containing, commas"'
list = re.findall(r'\w+=".*?"', vars)

for i in range(1,len(list)):
   print list[i]

输出如下：

VISIBILITY=","
SRC=","

但是我想找到（拆分）所有参数，即使是那些包含逗号的参数。输出应该是这样的：

"NAME=Product"
"TYPE="
"VERSION=1.2"
"VISIBILITY="
"SRC="
"FOLDER=TRUE"
"Text=foo, containing, commas"

我有什么要改变我的正则表达式？

Answer 1

您的正则表达式似乎只是期望=等号右边的值附近的引号，但您的输入在整个表达式周围都有引号。

调整很简单：

re.findall(r'"\w+=.*?"', vars)

在您的示例输入上运行该命令：

>>> re.findall(r'"\w+=.*?"', vars)
['"NAME=Product"', '"TYPE="', '"VERSION=1.2"', '"VISIBILITY="', '"SRC="', '"FOLDER=TRUE"', '"Text=foo, containing, commas"']
>>> for match in re.findall(r'"\w+=.*?"', vars):
...     print match
... 
"NAME=Product"
"TYPE="
"VERSION=1.2"
"VISIBILITY="
"SRC="
"FOLDER=TRUE"
"Text=foo, containing, commas"

Answer 2

我不确定你需要正则表达式：

[i for i in  vars.split('"') if i not in ',']

出：

['NAME=Product',
 'TYPE=',
 'VERSION=1.2',
 'VISIBILITY=',
 'SRC=',
 'FOLDER=TRUE',
 'Text=foo, containing, commas']

Answer 3

我猜这更接近你真正想要的东西：

 list = re.findall(r'"(\w+)=(.*?)"', VARS)

Answer 4

您可以使用CSV执行此操作：

import csv

vars='"NAME=Product","TYPE=","VERSION=1.2","VISIBILITY=","SRC=","FOLDER=TRUE","Text=foo, containing, commas"'
reader=csv.reader(vars,delimiter=",",quotechar='"')

print [''.join(tgt) for tgt in reader if ''.join(tgt)]

打印：

['NAME=Product', 'TYPE=', 
 'VERSION=1.2', 
 'VISIBILITY=', 
 'SRC=', 
 'FOLDER=TRUE', 
 'Text=foo, containing, commas']

Answer 5

import re

vari=('"NAME=Product",'
      '"TYPE=","VERSION=1.2",'
      '"VISIBILITY=","SRC=","FOLDER=TRUE",'
      '"Text=foo, containing, commas"')

print '\n'.join(re.findall('"[^"=]+=[^"=]*"', vari))

正则表达式搜索找不到包含内容的元素

5 个答案: