Question

我需要创建一个webservices包，它将通过其他域的javascript请求。

我很反感，有一个支持跨域的酷包：CORSFilter。

我看到，CORS的实现是添加到web.xml：

<web-app>
<filter>
    <filter-name>CORSFilter</filter-name>
    <filter-class>CORSFilter</filter-class>
</filter>
<filter-mapping>
    <filter-name>CORSFilter</filter-name>
    <url-pattern>/api/*</url-pattern>
</filter-mapping>

但我有自己的配置：

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

    <!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/root-context.xml</param-value>
    </context-param>

    <!-- Creates the Spring Container shared by all Servlets and Filters -->
    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <!-- Processes application requests -->
    <servlet>
        <servlet-name>appServlet</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>appServlet</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>



</web-app>

当我尝试将CORS配置添加到我的web.xml时：

<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">

<!-- The definition of the Root Spring Container shared by all Servlets and Filters -->
<context-param>
    <param-name>contextConfigLocation</param-name>
    <param-value>/WEB-INF/spring/root-context.xml</param-value>
</context-param>

<!-- Creates the Spring Container shared by all Servlets and Filters -->
<listener>
    <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>

<!-- Processes application requests -->
<servlet>
    <servlet-name>appServlet</servlet-name>
    <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
    <init-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>/WEB-INF/spring/appServlet/servlet-context.xml</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
</servlet>

<servlet-mapping>
    <servlet-name>appServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

<filter>
    <filter-name>corsFilter</filter-name>
    <filter-class>com.thetransactioncompany.cors.CORSFilter</filter-class>
</filter>

<filter-mapping>
    <filter-name>corsFilter</filter-name>
    <servlet-name>/*</servlet-name>
</filter-mapping>

我收到错误：

    mar 19, 2013 2:17:08 PM org.apache.catalina.core.StandardContext startInternal
SEVERE: Error filterStart
mar 19, 2013 2:17:08 PM org.apache.catalina.core.StandardContext startInternal
SEVERE: Context [] startup failed due to previous errors

我应该如何实施呢？

由于

Answer 1

在“filter-mapping”部分中，你有一个“servlet-name”标签，但里面的内容实际上是一个url模式，而不是一个servlet名称。所以你应该有

<servlet-name>appServlet</servlet-name>

或

<url-pattern>/*</url-pattern>

Answer 2

您应该考虑使用自Spring Framework 4.2 GA起提供的本机CORS支持。有关详细信息，请参阅this blog post。

如果您更喜欢继续使用基于Filter的方法，例如，如果您不使用Spring MVC而只使用Spring Web，则还会提供Spring CorsFilter。

Java Spring和CORS

2 个答案: