Question

我在执行下面的查询时遇到错误，但我无法找出问题所在。有人可以帮忙吗？

SELECT shifts.consultant_uid AS consultant_uid, shifts.status AS 
status , shifts.pay_roll_no AS pay_roll_no, shifts.week_ending AS week_ending, shifts.shifts_date AS shifts_date, shifts.description AS description, shifts.units AS units, shifts.pay_rate AS pay_rate, shifts.charge_rate AS charge_rate, shifts.pay_amount AS pay_amount, shifts.charge_amount AS charge_amount, shifts.margin_amount AS margin_amount, shifts.client_name AS client_name, consultant.user_name AS consultant_name, 

FROM a_shifts AS shifts

LEFT JOIN a_users AS consultant ON shifts.consultant_uid = consultant.user_uid
WHERE 1 

AND week_ending >=  '2013-03-17'
AND week_ending <=  '2013-03-24'

Answer 1

SELECT子句中字段列表的末尾有一个额外的逗号：

... consultant.user_name AS consultant_name,

作为一般建议，通常实际错误表示查询中遇到错误的位置。在大多数情况下，它指示的位置就在问题之后，因为这是查询遇到的第一个无法解析的问题（在这种情况下，FROM关键字）错误。

Answer 2

在FROM子句

之前删除

SELECT .........consultant.user_name AS consultant_name,
FROM

Answer 3

试试这个

SELECT shifts.consultant_uid AS consultant_uid, shifts.status AS 
status , shifts.pay_roll_no AS pay_roll_no, shifts.week_ending AS week_ending, shifts.shifts_date AS shifts_date, shifts.description AS description, shifts.units AS units, shifts.pay_rate AS pay_rate, shifts.charge_rate AS charge_rate, shifts.pay_amount AS pay_amount, shifts.charge_amount AS charge_amount, shifts.margin_amount AS margin_amount, shifts.client_name AS client_name, consultant.user_name AS consultant_name

FROM a_shifts AS shifts

LEFT JOIN a_users AS consultant ON shifts.consultant_uid = consultant.user_uid
WHERE 1 

AND week_ending >=  '2013-03-17'
AND week_ending <=  '2013-03-24'

MySQL Query中出现＃1064错误

3 个答案: