Question

我有2张桌子

CREATE TABLE `tbl_patient` (
    id_patient      INTEGER     NOT NULL PRIMARY KEY AUTO_INCREMENT,
    name            VARCHAR(25) NOT NULL DEFAULT "not available",
    att1            VARCHAR(5 ) NOT NULL DEFAULT "att1",
    att2            VARCHAR(25) NOT NULL DEFAULT "att2",
    att3            VARCHAR(25) NOT NULL DEFAULT "att3",
    CONSTRAINT `uc_Info_patient` UNIQUE (`id_patient`)           
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;

和

CREATE TABLE `tbl_patient_medicine` ( 
    id_patient_medicine INTEGER     NOT NULL PRIMARY KEY AUTO_INCREMENT,
    id_patient          INTEGER     NOT NULL,
    name_medicine       VARCHAR(50) NOT NULL DEFAULT "", 
    dosis               VARCHAR(50) NOT NULL DEFAULT "",         
    start_date          timestamp   NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, 
    treatment            VARCHAR(50) NOT NULL DEFAULT "", 
    times_per_day       VARCHAR(50) NOT NULL DEFAULT "",    
    CONSTRAINT fk_ID_Patient_Medicine  FOREIGN KEY (id_patient)   REFERENCES `tbl_patient`(id_patient)
) ENGINE=InnoDB  DEFAULT CHARSET=utf8 AUTO_INCREMENT=1;

如您所见，表patient_medicine是tbla_medicines和表患者之间的中间表。

现在我想咨询tbl_patient_medicine与杂货店like in this sqlfiddle

的所有数据

supossing我在uri中传递id（在示例中将是id_patient = 1）我有

public function details_medication($my_id = 0)
{   
  try{
    $crud = new grocery_CRUD();
    $crud->where('id_patient',$my_id);
    $crud->set_table('tbl_patient_medicine');


        //HOW TO DO IT? 
        $crud->set_relation('id_patient', 'tbl_patient', 'id_patient');


    $output = $crud->render();
        $this->_output($output); 

     }catch(Exception $e){
    show_error($e->getMessage().' --- '.$e->getTraceAsString());
     }      
}

所以我尝试了不同的方法，但是出现了这样的错误：

A Database Error Occurred

Error Number: 1052

Column 'id_patient' in where clause is ambiguous

SELECT `tbl_patient_medicine`.*, j7a675883.id_patient AS s7a675883 
FROM (`tbl_patient_medicine`) 
LEFT JOIN `tbl_patient` as j7a675883 
ON `j7a675883`.`id_patient` = `tbl_patient_medicine`.`id_patient` WHERE `id_patient` = '1' LIMIT 25

行号：87

Answer 1

我做了你的例子：

控制器：

function medicine() 

{
     $crud = new grocery_CRUD();

     $crud->set_table('tbl_patient_medicine');
     $crud->required_fields('id_patient','name_medicine','dosis','start_date','treatment','time_per_day');
     $crud->columns('id_patient','name_medicine','dosis','start_date','treatment','time_per_day');
     $crud->fields('id_patient','name_medicine','dosis','start_date','treatment','time_per_day');

     $crud->set_relation('id_patient','tbl_patient','name');

     $output = $crud->render();  

     $this->_example_output($output); 
}

有效！

<强>编辑：

$crud->set_relation('id_patient','tbl_patient','{name},  {att1},  {att2},  {att3}');

Answer 2

尝试更改WHERE j7a675883。id_patient

设置关系杂货crud错误

2 个答案: