乘法表sql

时间:2013-03-18 20:47:26

标签: sql database oracle

如何创建将输出multiplication table的SELECT查询 没有使用像连接或子查询这样的东西?可以使用一些新的支持表。

UPD:

select 
x " ",
x*x1 "1", x*x2 "2", x*x3 "3", x*x4 "4", x*x5 "5", x*x6 "6", x*x7 "7", x*x8 "8", x*x9 "9",        x*x10 "10"
from num, res
where rownum < 11;

4 个答案:

答案 0 :(得分:1)

SELECT 
    level AS C, 
    1*level AS R1, 
    2*level AS R2, 
    3*level AS R3, 
    4*level AS R4, 
    5*level AS R5, 
    6*level AS R6, 
    7*level AS R7, 
    8*level AS R8, 
    9*level AS R9, 
    10*level AS R10 
FROM dual CONNECT BY level < 11

请参阅?这里只有一个查询。并且不需要愚蠢的虚拟桌子填充。

答案 1 :(得分:0)

将值插入到单个表中,从表中选择两次,在两个表之间不提供连接,并保留笛卡尔积。

答案 2 :(得分:0)

select level*&n from dual connect by level<=10;

这里你可以给出你想要乘法表的任何数字。

答案 3 :(得分:0)

CREATE TABLE Multiplctable(c1 int ,c2 int ,c3 int,c4 int,c5 int,c6 int,c7 int,c8 int,c9 int ,c10 int,c11 int,c12 int)

DECLARE @Loopcon  int;--LOOP CONTROLL
Set @Loopcon=1;

WHILE(@Loopcon<=12)
    BEGIN;

            INSERT INTO Multiplctable 
            VALUES(@Loopcon*1,@Loopcon*2,@Loopcon*3,@Loopcon*4,@Loopcon*5,@Loopcon*6,
            @Loopcon*7,@Loopcon*8,@Loopcon*9,@Loopcon*10,@Loopcon*11,@Loopcon*12);

            SET @Loopcon=@Loopcon+1;
  END;



  SELECT M.c1 [1],M.c2 [2],M.c3 [3],M.c4 [4],M.c5 [5],M.c6 [6],M.c7 [7],M.c8 [8],M.c9 [9],M.c10 [10],M.c11 [11],M.c12 [12]
  FROM Multiplctable M