python中的简单TCP服务器

时间:2013-03-18 20:16:30

标签: python socketserver

新手在这里。我正在尝试使用SocketServer创建一个简单的TCP服务器进程请求。不知何故,handle()方法没有被调用。

版本:Linux上的2.4.3

以下是相关代码:

#!/usr/bin/python -u
import socket;
import SocketServer
import time;
import threading;
class EchoRequestHandler(SocketServer.BaseRequestHandler):

    def handle(self):
        # Echo the back to the client
        data = self.request.recv(1024)
        self.request.send(data)
        return
class MyThreads(threading.Thread):
    def __init__(self):
        self.server = None;
        threading.Thread.__init__(self);
    def run(self):
        if self.server == None:
            address = ('localhost', 40000);
            self.server = SocketServer.TCPServer(address, EchoRequestHandler);
            # The following line partially fixed the problem
            self.server.serve_forever();
if __name__ == '__main__':
    thr = MyThreads();
    thr.setDaemon(True);
    thr.start();
    # Connect to the server
    s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    s.connect(('localhost', 40000))
    # Send the data
    message = 'Hello, world'
    print 'Sending : "%s"' % message
    len_sent = s.send(message)
    # Receive a response
    print 'Sending : "%s"' % message
    response = s.recv(len_sent)
    print 'Received: "%s"' % response

代码正在创建套接字,我可以使用netstat从命令行看到它。但是在调试器(python -m pdb)中,我看不到方法run()执行的代码。并且handle()也没有被调用。所以它连接到套接字,但没有收到任何回复。

1 个答案:

答案 0 :(得分:2)

您需要调用serve_forever()SocketServer对象开始侦听连接。顾名思义,serve_forever()方法永远不会返回。鉴于这一事实,您可能希望在您的线程中调用它,以便继续执行其余代码。例如:

class MyThreads(threading.Thread):
    def __init__(self):
        self.server = None;
        threading.Thread.__init__(self);
    def run(self):
        if self.server == None:
            address = ('localhost', 40000);
            self.server = SocketServer.TCPServer(address, EchoRequestHandler);

        self.server.serve_forever()

如果您的客户端代码在套接字侦听之前尝试连接,则可能会遇到竞争条件。可能time.sleep(...)会帮助你。