Question

我正在创建一个tic tac toe游戏作为一个带有二维数组的项目，我在检查斑点时遇到了一些问题，看看是否有胜利者。有人可以帮我调试吗？这是checkwinner函数和main函数。

char CheckWinner( char board[3][3])
{
    int i = 0;
    int j = 0;

                    if ( board[i][j] =='X' && board[i][j+1] == 'X' && board[i][j+2]== 'X' )
                    { W = X;}
                    else if (board[i+1][j] && board[i+1][i+1] && board[i+1][j+2]== 'X' )
                    { W = X;}
                    else if (board[i+2][j] && board[i+2][j+1] && board[i+2][j+2]== 'X')
                    { W = X;}
                    else if (board[i][j] && board[i+1][j] && board[i+2][j]== 'X')
                    { W = X;}
                    else if (board[i][j+1] && board[i+1][j+1] && board[i+2][j+1]== 'X')
                    { W = X;}
                    else if (board[i][j+2] && board[i+1][j+2] && board[i+2][j+2]== 'X')
                    { W =X;}
                    else if (board[i][j] && board[i+1][j+1] && board[i+2][j+2]=='X')
                    { W = X;}
                    else if (board[i+2][j] && board[i+1][j+1] && board[i][j+2]== 'X')
                    { W = X;}

                    else if (board[i][j] && board[i][j+1] && board[i][j+2]== 'O' )
                    { W = O;}
                    else if (board[i+1][j] && board[i+1][j+1] && board[i+1][j+2]== 'O')
                    { W = O;}
                    else if (board[i+2][j] && board[i+2][j+1] && board[i+2][j+2]== 'O')
                    { W = O;}
                    else if (board[i][j] && board[i+1][j] && board[i+2][j]== 'O')
                    { W = O;}
                    else if (board[i][j+1] && board[i+1][j+1] && board[i+2][j+1]== 'O')
                    { W = O;}
                    else if (board[i][j+2] && board[i+1][j+2] && board[i+2][j+2]== 'O')
                    { W = O;}
                    else if (board[i][j] && board[i+1][j+1] && board[i+2][j+2]== 'O')
                    { W = O;}
                    else if (board[i+2][j] && board[i+1][j+1] && board[i][j+2]== 'O')
                    { W = O;}



    return W;
}
int main () 
{ 
    char board[3][3];
    char Win = CheckWinner(board);
    int r = 0;


    InitializeBoard(board);

     for (int r = 0; r < 4 ; r++)
     { 
        PlayX(board);
        PlayO(board); 
        PrintBoard(board);
    }
     CheckWinner(board);
     cout << Win ;

    if (Win == X)
    {
        cout << "The winner is Player 1.";
    }
    else if (Win == O)
    {
        cout << "The winner is Player 2.";
    }
    else if (Win == TIE)
    {
        cout << " IT'S A TIE";
    }
    else; 


    system("PAUSE");
return 0;

Answer 1

您可以使用以下内容优化条件代码：

typedef char piece;

piece iswin() const
{
    piece ret = 'T';

    // Checks for horizontal win
    for (int i = 0; i < 3; ++i)
        if (*arr[i] == arr[i][1] && arr[i][1] == arr[i][2])
            if ((ret = *arr[i]) != 'T')
                return ret;

    // Checks for vertical win
    for (int i = 0; i < 3; ++i)
        if (arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i])
            if ((ret = arr[0][i]) != 'T')
                return ret;

    // Check for diagonal win (upper left to bottom right)
    if (**arr == arr[1][1] && arr[1][1] == arr[2][2])
        if ((ret = **arr) != 'T')
            return ret;

    // Check for diagonal win (upper right to bottom left)
    if (arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0])
        if ((ret = arr[0][2]) != 'T')
            return ret;

    return ret;
}

// checking the result:
switch (winner) {
    case 'T': /* tie */ break;
    case 'X': /* X won */ break;
    case 'O': /* O won */ break;
}

这有点清洁。它会做6个循环而不是9个循环。

Answer 2

您立即将CheckWinner结果分配给Win，然后玩游戏，然后再次致电CheckWinner，而不将结果分配给Win。因此，当您检查以下行中的Win时，您将获得原始结果，即电路板甚至未初始化时。

Answer 3

可能与将文字O或X分配到应该是char的返回值有关。因此，代替O或X，它应该是'O'或'X'。除非在发布的代码之外将O或X定义为char变量。

如何在tic tac toe游戏中为获胜者检查2维数组

3 个答案: