Question

我是关于iOS开发的新手。当我用NSJSONSerialization处理一个json时，我发现一些问题对我来说很重要。

NSLog(@"response: %@", responseString);
NSData *jsonData = [responseString dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *dict = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];
NSLog(@"dict: %@", dict);

，输出为：

2013-03-18 20:13:56.228 XXXX[3550:5003] response: {"status":"success","data":"{\"title\":\"\",\"sessionName\":\"sid\",\"sessionID\":\"9217e5df3db6b4b4aa3eed800890069f\",\"rand\":5360}","md5":"292ee1e78628fc6360c647e938c4f1ea"}
2013-03-18 20:13:56.229 XXXX[3550:5003] dict: {
data = "{\"title\":\"\",\"sessionName\":\"sid\",\"sessionID\":\"9217e5df3db6b4b4aa3eed800890069f\",\"rand\":5360}";
md5 = 292ee1e78628fc6360c647e938c4f1ea;
status = success;

使用“\”数据部分不能是NSDictionary对象

那么我应该怎样做才能做到正确？

抱歉我的英语不好。

Answer 1

无论出于何种原因，“data”的值不是JSON字典，而是包含JSON数据的字符串。您可以通过再次将JSONObjectWithData应用于此字符串并替换字典中的值来解决此问题：

NSData *jsonData = [responseString dataUsingEncoding:NSUTF8StringEncoding];
NSMutableDictionary *dict = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:nil];

NSData *nestedJsonData = [[dict objectForKey:@"data"] dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *nestedDict = [NSJSONSerialization JSONObjectWithData:nestedJsonData options:NSJSONReadingMutableContainers error:nil];

[dict setObject:nestedDict forKey:@"data"];
NSLog(@"dict: %@", dict);

输出：

dict: {
    data =     {
        rand = 5360;
        sessionID = 9217e5df3db6b4b4aa3eed800890069f;
        sessionName = sid;
        title = "";
    };
    md5 = 292ee1e78628fc6360c647e938c4f1ea;
    status = success;
}

如何删除NSString对象中的Superfluous Escape字符

1 个答案: