Question

此代码在行Parse error: syntax error, unexpected T_STRING处提供解析错误$gender=$user['gender']; .....这段代码中有错误...需要帮助.....谢谢

<?php
 require_once 'config/functions.php';
 session_start();
 $user=$_SESSION['google_data'];
 if(!empty($user)){
  $email = $user['email'];
  $fname = $user['given_name'];
  $lname = $user['family_name'];
  $gender=$user['gender'];
  $dob = $user['birthday'];
  $location = '';
  $picture = $user['picture'];
  $uid = $user['id'];
  $ousername = '';
  $link = $user['link'];
       $provider = 'google';
       $verified = $user['verified_email'];

      $gen=0;
      if($gender == 'male'){$gen=1;} else{$gen=0;}
      $new_dob = date( "Y-m-d H:i:s", strtotime($dob) );

      $userObj = new User();
      $userdata = $userObj->checkUser($email,$fname,$lname,$gen,$new_dob,$location,$picture,$uid,$ousername,$link,$provider,$new_verified); 
      if(!empty($userdata)){         
        $_SESSION['id'] = $userdata['user_id'];
        $_SESSION['oauth_id'] = $userdata['user_oauth_id'];
        $_SESSION['username'] = $userdata['user_oauth_username'];
        $_SESSION['picture'] = $userdata['picture'];            
        $_SESSION['link'] = $userdata['link'];
        $_SESSION['fname'] = $userdata['user_fname'];
        $_SESSION['lname'] = $userdata['user_lname'];
        $_SESSION['gender'] = $userdata['user_gender'];
        $_SESSION['email'] = $userdata['user_email'];
        $_SESSION['oauth_provider'] = $userdata['user_oauth_provider'];             
        $_SESSION['oauth_id'] = $uid;


     } else {
        # For testing purposes, if there was an error, let's kill the script
        die("There was an error.");

    }
  }
 ?>

Answer 1

这一行可能是问题所在：


     }
     } else {

Answer 2

你需要删除最后一个额外的}。

所以最后一行将是。

} else {
      # For testing purposes, if there was an error, let's kill the script
      die("There was an error.");
 }

<强> CompleteCode

<?php
    require_once 'config/functions.php';
    session_start();
    $user=$_SESSION['google_data'];

    if(!empty($user))
    {
        $email = $user['email'];
        $fname = $user['given_name'];
        $lname = $user['family_name'];
        $gender=$user['gender'];
        $dob = $user['birthday'];
        $location = '';
        $picture = $user['picture'];
        $uid = $user['id'];
        $ousername = '';
        $link = $user['link'];
        $provider = 'google';
        $verified = $user['verified_email'];

        $gen=0;
        if($gender == 'male'){$gen=1;} else{$gen=0;}

        $new_dob = date( "Y-m-d H:i:s", strtotime($dob) );

        $userObj = new User();
        $userdata = $userObj->checkUser($email,$fname,$lname,$gen,$new_dob,$location,$picture,$uid,$ousername,$link,$provider,$new_verified); 

        if(!empty($userdata))
        {
            $_SESSION['id'] = $userdata['user_id'];
            $_SESSION['oauth_id'] = $userdata['user_oauth_id'];
            $_SESSION['username'] = $userdata['user_oauth_username'];
            $_SESSION['picture'] = $userdata['picture'];            
            $_SESSION['link'] = $userdata['link'];
            $_SESSION['fname'] = $userdata['user_fname'];
            $_SESSION['lname'] = $userdata['user_lname'];
            $_SESSION['gender'] = $userdata['user_gender'];
            $_SESSION['email'] = $userdata['user_email'];
            $_SESSION['oauth_provider'] = $userdata['user_oauth_provider'];             
            $_SESSION['oauth_id'] = $uid;

        }
    }
    else
    {
        die("There was an error.");
    }
?>

Answer 3

请像这样使用

$gender = isset( $user['gender'] ) ? $user['gender'] : '' ;

我的代码中有什么错误，它给出了解析错误

3 个答案: