Question

循环遍历字符串并用单个空格替换双空格的开销花费了太多时间。尝试用单个空格替换字符串中的多个间距是一种更快的方法吗？

我一直都是这样做的，但这太长了，太浪费了：

str1 = "This is    a  foo bar   sentence with  crazy spaces that  irritates   my program "

def despace(sentence):
  while "  " in sentence:
    sentence = sentence.replace("  "," ")
  return sentence

print despace(str1)

Answer 1

看看这个

In [1]: str1 = "This is    a  foo bar   sentence with  crazy spaces that  irritates   my program "

In [2]: ' '.join(str1.split())
Out[2]: 'This is a foo bar sentence with crazy spaces that irritates my program'

方法split()返回字符串中所有单词的列表，使用str作为分隔符（如果未指定则拆分所有空格）

Answer 2

使用regular expressions：

import re
str1 = re.sub(' +', ' ', str1)

' +'匹配一个或多个空格字符。

您还可以用

替换所有空格

str1 = re.sub('\s+', ' ', str1)

用单个空格替换字符串中的多个间距 - Python

2 个答案: