Oracle SQL将多行插入到具有一系列日期的表中

Question

我找到了相关问题的以下答案。

with calendar as(
    select :startdate + rownum - 1 as day
    from dual
    connect by rownum < :enddate - startdate
)
select rownum as "S.No", to_date(day,'dd_mm_yyyy') as "Cal_Dt", to_char(day,'day') as "DayName"
from calendar

此SQL为一系列日期生成许多日期和相关信息。有些正文可以告诉我如何将其包装到SQL语句中，以便可以将select（所有行）中的内容插入到另一个表中。

Answer 1

如果要插入数据的表已存在，请使用INSERT INTO：

with calendar as ( 
    select :startdate + rownum - 1 as day 
    from dual 
    connect by rownum < :enddate - startdate ) 
insert into anothertable (no, dt, dayname)
select rownum as "S.No", to_date(day,'dd_mm_yyyy') as "Cal_Dt", to_char(day,'day') as "DayName" 
from calendar

或使用SELECT INTO语法创建新表：

with calendar as ( 
    select :startdate + rownum - 1 as day 
    from dual 
    connect by rownum < :enddate - startdate ) 
select rownum as "S.No", to_date(day,'dd_mm_yyyy') as "Cal_Dt", to_char(day,'day') as "DayName" into newtable
from calendar

<击> 编辑 - 实际上评论是完全正确的 - 没有考虑Oracle :-)这是从Oracle中的SQL语句创建表的正确方法：

with calendar as ( 
    select :startdate + rownum - 1 as day 
    from dual 
    connect by rownum < :enddate - startdate ) 
CREATE TABLE newtable
AS 
(select rownum as "S.No", to_date(day,'dd_mm_yyyy') as "Cal_Dt", to_char(day,'day') as "DayName"
from calendar)

Answer 2

伪列LEVEL也可以正常工作

insert into tgt_tbl(id,dt,dy)
select distinct level,:startdate+level-1,to_char(:startdate+level-1,'Day') from dual
connect by level<=(:enddate-:startdate)+1

Answer 3

CREATE TABLE DATES_TABLE 
(
  Date_Field   DATE
);

INSERT INTO DATES_TABLE
(
  Date_Field
)
SELECT ROWNUM - 1 + TO_DATE('01-Jun-2004','dd-mon-yyyy') Date_Field
FROM all_objects
WHERE ROWNUM < TO_DATE('30-Jun-2004','dd-mon-yyyy') - TO_DATE('01-Jun-2004','dd-mon-yyyy') + 2;

尝试更改这些日期值以获得所需范围内的日期值