Question

我正在创建这个rails应用，在应用程序中，我具有创建帐户的功能，然后发布状态。我已经做到了所以我可以在屏幕上显示状态，但是我如何显示发布帖子的人的姓名？我正在使用设计并设置：用户名

我的观点

<% if user_signed_in? %>
  <h1 id="welcome" class="nuvo">Welcome <%= current_user.username %>!</h1>
<% else %>
  <h1 id="welcome" class="nuvo">Log-In to make some posts!</h1>
<% end%>

<div class="follow-row">
  <div class="titan-users nuvo"><h2>TITAN Users</h2></div>
</div>

<div class="statuses">
  <% if user_signed_in? %><div class="status-form"><%= render 'form' %></div><% end %>
  <% @posts.each do |post| %>
    <div class="post">
      <div class="tstamp"><strong>Posted <%= time_ago_in_words(post.created_at) %> ago by <%= current_user.username %></strong></div>
      <div class="status"><%= post.status %></div>
    </div>
  <% end %>
</div>

我的帖子控制器

class PostsController < ApplicationController
  # GET /posts
  # GET /posts.json
  def index
    @posts = Post.all(:order => "created_at DESC")
    @post = Post.new

    respond_to do |format|
      format.html # index.html.erb
      format.json { render json: @posts }
    end
  end

  # GET /posts/1
  # GET /posts/1.json
  def show
    redirect_to posts_path
  end

  # GET /posts/new
  # GET /posts/new.json
  def new
    @post = Post.new

    respond_to do |format|
      format.html # new.html.erb
      format.json { render json: @post }
    end
  end

  # GET /posts/1/edit
  def edit
    @post = Post.find(params[:id])
  end

  # POST /posts
  # POST /posts.json
  def create
    @post = Post.new(params[:post])

    respond_to do |format|
      if @post.save
        format.html { redirect_to @post, notice: 'Post was successfully created.' }
        format.json { render json: @post, status: :created, location: @post }
      else
        format.html { render action: "new" }
        format.json { render json: @post.errors, status: :unprocessable_entity }
      end
    end
  end

  # PUT /posts/1
  # PUT /posts/1.json
  def update
    @post = Post.find(params[:id])

    respond_to do |format|
      if @post.update_attributes(params[:post])
        format.html { redirect_to @post, notice: 'Post was successfully updated.' }
        format.json { head :no_content }
      else
        format.html { render action: "edit" }
        format.json { render json: @post.errors, status: :unprocessable_entity }
      end
    end
  end

  # DELETE /posts/1
  # DELETE /posts/1.json
  def destroy
    @post = Post.find(params[:id])
    @post.destroy

    respond_to do |format|
      format.html { redirect_to posts_url }
      format.json { head :no_content }
    end
  end
end

我的用户模型

class User < ActiveRecord::Base
  # Include default devise modules. Others available are:
  # :token_authenticatable, :confirmable,
  # :lockable, :timeoutable and :omniauthable
  devise :database_authenticatable, :registerable,
         :recoverable, :rememberable, :trackable, :validatable

  # Setup accessible (or protected) attributes for your model
  attr_accessible :email, :password, :password_confirmation, :remember_me, :username

  has_many :post
  # attr_accessible :title, :body
end

我的帖子模型

class Post < ActiveRecord::Base
  attr_accessible :status, :author

  belongs_to :user

  validates :status, :presence => true
end

那么，有没有人有任何想法如何在视图中显示，'current_user.username'可以显示发布它的人的姓名吗？

因此，对于CodeIt，这是我得到的错误

undefined method `username' for nil:NilClass
Extracted source (around line #17):

14:   <% if user_signed_in? %><div class="status-form"><%= render 'form' %></div><% end %>
15:   <% @posts.each do |post| %>
16:     <div class="post">
17:       <div class="tstamp"><strong>Posted <%= time_ago_in_words(post.created_at) %> ago by <%= post.user.username %></strong></div>
18:       <div class="status"><%= post.status %></div>
19:     </div>
20:   <% end %>
20:   <% end %>`

Answer 1

您拥有post belongs_to user。所以你可以使用：

 post.user.username  #In your @posts loop

Answer 2

在控制器的create方法中，我没有看到你将user_id传递给它，所以可能是用户dint设置为post模型。

也许您可以在表单中放入hidden_field_tag，并将您的user_id作为参数传递。然后，在您的控制器中，执行类似的操作 @ post.user_id = params [：user_id]

然后，在您的视图中，您可以访问user_id并从user_id

中查找用户名

设计 - 尝试显示发帖的用户

2 个答案: