Question

我在下面有一个简单的函数，它可以获得秒数，然后像＃34; 2分钟前一样返回＆＃34;，＆＃34; 9小时前＆＃34;等...

如果我通过1＆lt; relativedate（）＆＃39;功能它只会返回1秒，依此类推。众所周知60 * 60 * 24 * 7 * 30或18144000sec = 1个月。因此，如果我在参数上传递值18144000，它应该返回1个月。但是，如果我在参数上传递一个值，请在relativedate（）上说231440000，这应该超过一年，它将返回＆＃39; 13个月＆＃39;而不是1年。

function relativedate($secs) {
        $second = 1;
        $minute = 60;
        $hour = 60*60;
        $day = 60*60*24;
        $week = 60*60*24*7;
        $month = 60*60*24*7*30;
        $year = 60*60*24*7*30*365;

        if ($secs <= 0) { $output = "now";
        }elseif ($secs > $second && $secs < $minute) { $output = round($secs/$second)." second";
        }elseif ($secs >= $minute && $secs < $hour) { $output = round($secs/$minute)." minute";
        }elseif ($secs >= $hour && $secs < $day) { $output = round($secs/$hour)." hour";
        }elseif ($secs >= $day && $secs < $week) { $output = round($secs/$day)." day";
        }elseif ($secs >= $week && $secs < $month) { $output = round($secs/$week)." week";
        }elseif ($secs >= $month && $secs < $year) { $output = round($secs/$month)." month";
        }elseif ($secs >= $year && $secs < $year*10) { $output = round($secs/$year)." year";
        }else{ $output = " more than a decade ago"; }

        if ($output <> "now"){
            $output = (substr($output,0,2)<>"1 ") ? $output."s" : $output;
        }
        return $output;
    }



echo relativedate(60); // 1 minute

Answer 1

您的年度计算为365个月，而不是12个月

php返回日期/时间问题

1 个答案: