我正在编写一个分组超过两列的查询。这意味着,它会将Col1和Col2放在同一组中。
如何根据Group Col1进行记录总结?
到目前为止我有这个:http://sqlfiddle.com/#!3/eada2/1
谢谢
答案 0 :(得分:0)
我能够解决它如下:
WITH cteActivityIds (activityId, allDocuByActivity)
AS
(SELECT activityId, COUNT(*) AS allDocuByActivity FROM #ER GROUP BY activityId)
SELECT
E.activityId AS [Actiivty ID],
docuType AS [Docu Type],
COUNT(docuType),
CONVERT(DECIMAL(16,2), (COUNT(docuType) * 100.00 / t.allDocuByActivity)) [Total DocuType in Activity],
SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) AS [Sent],
SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) AS [Approved]
FROM
#ER AS E
INNER JOIN cteActivityIds AS t
ON E.activityId = t.activityId
GROUP BY
E.activityId, docuType, t.allDocuByActivity
谢谢
答案 1 :(得分:0)
这是一个解决方案,在我看来,看起来更清洁一点 - 它不需要连接并使用'partition by'来计算个别计数:
WITH activityCounts as (
select
activityId,
docuType,
count(activityId) OVER(PARTITION BY activityId) as activityIdCount,
count(docuType) OVER(PARTITION BY activityId, docuType) as docuTypeCount,
SUM(CASE WHEN [sent] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Sent],
SUM(CASE WHEN [approved] != '1-1-1900' THEN 1 END) OVER(PARTITION BY activityId, docuType) AS [Approved]
from ER
)
SELECT
activityId,
docuType,
docuTypeCount,
CONVERT(DECIMAL(16,2), (COUNT(docuTypeCount) * 100.00 / activityIdCount)) as [Total DocuType in Activity],
[Sent],
[Approved]
FROM activityCounts
GROUP BY
activityId,
docuType,
activityIdCount,
docuTypeCount,
[Sent],
[Approved]
答案 2 :(得分:0)
您只需要在t.allDocuByActivity
MIN(t.allDocuByActivity) AS [Total DocuType in Activity],
但是,由于您的标签为DocuType
。你不需要DISTINCT
吗?