Question

我是一名C ++初学者，我正在尝试定义一个BubbleSort函数来对链表中的元素进行排序。但是

发生错误

for(current = firstPtr ; current != 0 ; current= current ->nextPtr)

说

First-chance exception at 0x01375557 in 111.exe: 0xC0000005: Access violation reading  location 0x00000000.
Unhandled exception at 0x01375557 in 111.exe: 0xC0000005: Access violation reading location 0x00000000.

以下是核心代码：

 //define Node in class List
 //Node.h
 template<typename T> class List;

template<typename T>
class Node{
friend class List<T>;

public:
Node(T &); //constructor
    T getData() const; //access data

private:
T data;
Node<T> *nextPtr; //point to the next Node
};

template<typename T>
Node<T> ::Node(T &key):data(key),nextPtr(0){}

template<typename T>
T Node<T>::getData()const{
return data;
}


//clase List
//List.h
#include<iostream>
#include"Node.h"
using namespace std;

template <typename T>
class List{
public:
List();
    void insertAtFront(T );
void insertAtBack( T &);
bool removeFromFront(T &);
bool removeFromBack(T &);
bool isEmpty() const;
void print() const;
    void BubbleSort();
private:
Node<T> *firstPtr;
Node<T> *lastPtr;

Node<T> *getNewNode(T&);

};

template<typename T>
List<T> :: List():firstPtr(0),lastPtr(0){}

template<typename T>
void List<T>::BubbleSort(){
Node<T> *current;  //Point to the current node
Node<T> *temp = firstPtr;  //hold the data of first element
    for(bool swap = true; swap;){  // if no swap occurs, list is in order
     swap =false;         
     for(current = firstPtr ; current != 0 ; current= current ->nextPtr){
         if (current->data > current->nextPtr->data){  //swap data
             temp->data = current->data;
             current->data = current->nextPtr->data;
             current->nextPtr->data = temp ->data;
             swap = true;
         }

     }
  }
}

你能帮我解决一下吗？我用过调试但仍无法找到解决方案。谢谢。

Answer 1

在内部循环中，当您尝试查看其数据时，假设current->nextPtr不为空。列表中的最后一个节点不是这种情况。尝试从

更改内循环条件

current != 0

到

current != 0 && current->nextPtr != 0

C ++冒泡排序链接列表

1 个答案: