如何在WPF中从另一个WPF表单设置TextBox或Label文本

时间:2013-03-16 19:08:08

标签: c# wpf binding textbox label

我在c#中更新WPF表单中的TextBox文本时遇到问题。我已经以编程方式创建了新表单并添加了一个Label和一个TextBox,并且我有一个变量temp,它表示我之前创建的某个缓冲区中的某个字符串。但是,当我尝试将文本设置为标签或文本框时,没有任何反应。但是,我可以用新的形式更改窗口标题。

我的代码是:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Threading;
using System.Threading.Tasks;
using System.Windows;
using System.Windows.Controls;
using System.Windows.Data;
using System.Windows.Documents;
using System.Windows.Input;
using System.Windows.Media;
using System.Windows.Media.Imaging;
using System.Windows.Navigation;
using System.Windows.Shapes;

namespace BufferProba
{
    /// <summary>
    /// Interaction logic for MainWindow.xaml
    /// </summary>
    public partial class MainWindow : Window
    {
        BufferStream bfStream = new BufferStream();

        private static Action EmptyDelegate = delegate() { };

        public MainWindow()
        {
            InitializeComponent();
        }

        private void Window_Loaded(object sender, RoutedEventArgs e)
        {

            Thread t = new Thread(SetText);
            t.SetApartmentState(ApartmentState.STA);
            t.IsBackground = true;
            t.Start();

        }


        private void Button_Click_1(object sender, RoutedEventArgs e)
        {
            bfStream.put(tBox.Text.Trim());
            tBox.Text = "";
        }


        public void SetText()
        {
            Thread.Sleep(5000);

            Window myWindow = new Window();
            StackPanel stackPanel = new StackPanel { Orientation = Orientation.Vertical };
            TextBox tboxForm = new TextBox();
            Label szzr = new Label { Content = "" };
            stackPanel.Children.Add(szzr);
            stackPanel.Children.Add(tboxForm);
            myWindow.Content = stackPanel;
            List<String> listaStringova = new List<String>();

            while (true)
            {
                Thread.Sleep(5000);

                String temp = bfStream.get();
                listaStringova.Add(temp);

                if (temp != "0")
                {
                    //Console.WriteLine(temp);
                   myWindow.Title = temp;
                   szzr.Content = temp;
                   szzr.Background = new SolidColorBrush(Colors.Orange);
                   szzr.UpdateLayout();
                   tboxForm.Text = temp;
                   myWindow.Show();

                }
                else { 
                    MessageBox.Show("Jebiga");
                }

            }
        }


    }
}

2 个答案:

答案 0 :(得分:0)

您需要确保它是访问TextBox的UI线程。使用Dispatcher.CheckAccess方法,如果返回false,则BeginInvoke UI线程。您应该能够在网上找到大量有关此信息的示例。

答案 1 :(得分:0)

您应该在主线程上运行它。  您可以使用Dispatcher执行相同的操作 例如:

System.Windows.Application.Current.Dispatcher.Invoke(new Action(SetText()))