Question

我有一个数组包含来自输入的chars，另一个数组包含指向第一个数组中相应chars的指针。这部分很顺利。

但是我想对char**数组（指针数组）进行冒泡排序，以便原始数组保持不变，但出现错误（文本未排序）。

EDIT: Please discuss only the sorting algorithm


 char tab[200];//array of chars 
 char** t = new char*[tabLength];
 //SOMETHING
....

....
int n = tabLength;//length of tab(length of the word it contains)
//TILL HERE EVERYTHING IS FINE -----------------------------------
         //bubble sorting below
do{
    for(int i = 0; i < n -1; i++){
        if(*t[i] > *t[i+1]){
            char* x = t[i];
            t[i] = t[i+1];
            t[i+1] = x;
        }
        n--;
    }
}while(n>1);

cout<<"sorted input";
for(int i = 0; i < tabLength; i++)
    cout<<t[i];
    cout<<endl;

cout<<"original"<<tab<<endl;

Answer 1

确保打印出指针指向的值：

for(int i = 0; i < tabLength; i++)
  cout << *t[i];

Answer 2

我只想使用标准库中已有的功能：

#include <iostream>
#include <string>
#include <algorithm>

int main()
{
    std::string original;
    std::getline(std::cin, original);

    std::cout << '|' << original << "|\n";

    std::string sorted = original;
    std::sort(std::begin(sorted), std::end(sorted));

    std::cout << "Sorted  : " << sorted << '\n';
    std::cout << "Original: " << original << '\n';
}

试运行：

|Hello world, how are you doing today?|
Sorted  :       ,?Haadddeeghilllnoooooorrtuwwyy
Original: Hello world, how are you doing today?

如何将指针数组排序到另一个字符数组

2 个答案: