如何为ImageGrid中的每个子图添加标题,为整个图添加单个xlabel / ylabel?

时间:2013-03-16 00:57:42

标签: python matplotlib

我使用mpl_toolkits.axes_grid1创建了下图:

enter image description here

但出于某种原因,我的子标题标题没有出现。我该怎么办呢?

代码:

# import 
from mpl_tookits.axes_grid1 import ImageGrid
from matplotlib.pyplot import *

fig = figure(figsize=(20, 12), dpi=300)
grid = ImageGrid(fig, 111, nrows_ncols=(3, 4), axes_pad=1, aspect=False)
for gridax, (i, sub) in zip(grid, enumerate(eyelink_data)):
    subnum = i + start_with

     # format data
    xdat = sub['x'][(sub['in_trl'] == True) & (sub['x'].notnull()) & (sub['y'].notnull())]
    ydat = sub['y'][(sub['in_trl'] == True) & (sub['x'].notnull()) & (sub['y'].notnull())]

    # plot
    gridax.hist2d(xdat, ydat, bins=[np.linspace(-.005, .005, num=1000), np.linspace(-.005, .005, num=1000)])
    gridax.plot(0, 0, 'ro')  # origin

    title('Subject {0} in-Trial Gaze'.format(subnum))
    xlabel('Horizontal Offset\n(degrees visual angle)')
    ylabel('Vertical Offset\n(degrees visual angle)')

show()

P.S。:享受grid illusion

1 个答案:

答案 0 :(得分:4)

如果您想要每个子图的标题,您只需对该轴使用title命令即可。你在哪里:

title('Subject {0} in-Trial Gaze'.format(subnum))

只需写下:

gridax.set_title('Subject {0} in-Trial Gaze'.format(subnum))

如果您想要一个大的xlabelylabel,则必须围绕网格制作一个大的axes对象。我不是专家,但这应该有所帮助:

Multiple Subplots with One Axis Label