Question

我刚刚开始将我的网站从mysql转换为mysqli，并将我的一个函数更改为mysqli。我上传了这个新功能，但现在没有从数据库中显示任何结果。那么这只是代码，还是整个网站在函数运行之前必须先在mysqli中？可能是因为我的数据库连接仍然是mysql？我转换了这个

function viewOrdersAdmin(){
//This block grabs the orders
$order_list = "";
//Selecting all the orders in the table from that member
$sql = mysql_query("SELECT * FROM `transactions`");

while ($transactions = mysql_fetch_array($sql)) {
    //creating variables from the information
    $order_id = $transactions["order_id"];
    $mem_id = $transactions["mem_id"];

    $order_details = mysql_query("SELECT * FROM `transactionDetails` WHERE `order_id` = $order_id GROUP BY order_id");
    $orderDetailsCount = mysql_num_rows($order_details);
    while ($row = mysql_fetch_array($order_details)) {
        //creating variables from the information
        $order_product_id = $row["Product_ID"];

        $member_details = mysql_query("SELECT * FROM `members` WHERE `mem_id` = $mem_id");
        $memberDetailsCount = mysql_num_rows($member_details);
        while ($row2 = mysql_fetch_array($member_details)) {
            //creating variables from the information
            $order_mem_fname = $row2["mem_first_name"];
            $order_mem_lname = $row2["mem_last_name"];

        $order_list .= "Order ID:$order_id - Customer Name: $order_mem_fname $order_mem_lname  &nbsp; &nbsp; &nbsp; <a href='manage_order.php?orderid=$order_id'>View</a> &bull; <a href='manage_orders.php?deleteid=$order_id'>Delete</a><br/>";

        }
    }
}

if (count($orderDetailsCount) == 0) {
    $order_list = "You have no orders to display";
}

print_r($order_list);
}

到此

function viewOrdersAdmin(){ 
//This block grabs the orders 
$order_list = ""; 
//Selecting all the orders in the table from that member 
$sql = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM `transactions`"); 

while ($transactions = mysqli_fetch_array($sql)) { 
    //creating variables from the information 
    $order_id = $transactions["order_id"]; 
    $mem_id = $transactions["mem_id"]; 

    $order_details = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM `transactionDetails` WHERE `order_id` = $order_id GROUP BY order_id"); 
    $orderDetailsCount = mysqli_num_rows($order_details); 
    while ($row = mysqli_fetch_array($order_details)) { 
        //creating variables from the information 
        $order_product_id = $row["Product_ID"]; 

        $member_details = mysqli_query($GLOBALS["___mysqli_ston"], "SELECT * FROM `members` WHERE `mem_id` = $mem_id"); 
        $memberDetailsCount = mysqli_num_rows($member_details); 
        while ($row2 = mysqli_fetch_array($member_details)) { 
            //creating variables from the information 
            $order_mem_fname = $row2["mem_first_name"]; 
            $order_mem_lname = $row2["mem_last_name"]; 

        $order_list .= "Order ID:$order_id - Customer Name: $order_mem_fname $order_mem_lname  &nbsp; &nbsp; &nbsp; <a href='manage_order.php?orderid=$order_id'>View</a> &bull; <a href='manage_orders.php?deleteid=$order_id'>Delete</a><br/>"; 

        } 
    } 
} 

if (count($orderDetailsCount) == 0) { 
    $order_list = "You have no orders to display"; 
} 

print_r($order_list);

}

Answer 1

如果要同时使用两个不同的库，则需要两个数据库连接：一个mysql连接和一个单独的mysqli连接。

但是，您可以同时使用两者而不会出现任何问题。它只会暂时使用更多资源，因为您有两个连接到通常有数据库的数据库。

顺便说一下，我不建议为数据库连接使用全局变量，你应该将它作为参数传递给你的函数，因为这样可以更容易地解决问题。

您还应该使用预准备语句来避免任何SQL注入问题。

当我转换时，一个网站可以成为mysql和mysqli的一部分

1 个答案: