Question

我正在尝试对字符串进行url编码，但NSURLConnection由于“错误的网址”而失败。这是我的网址：

    NSString *address = mp.streetAddress;
    NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
    NSString *cityState= mp.cityState;
    NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

    NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", encodedAddress, encodedCityState];
    NSURL *url = [NSURL URLWithString:fullAddressURL];

以下是API调用URL的示例：

下面是一个调用API的地址匹配“2114 Bigelow Ave”，“Seattle，WA”的地址的示例：

http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA

由于某种原因，此URL无法连接。有人可以帮助我吗？

Answer 1

您必须先对fullAddressURL进行编码，然后再将其发送至NSURL，而不是编码地址＆amp; cityState。

NSString *address = @"2114 Bigelow Ave";
//NSString *encodedAddress = [address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSString *cityState= @"Seattle, WA";
// NSString *encodedCityState = [cityState stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

NSString *fullAddressURL = [NSString stringWithFormat:@"http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<X1-ZWz1bivd5de5mz_8xo7s>&address=%@&citystatezip=%@", address, cityState];
fullAddressURL = [fullAddressURL stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];
NSLog(@"fullAddressURL: %@",fullAddressURL);

NSURL *url = [NSURL URLWithString:fullAddressURL];

我已经测试了上面的代码，它给出了与给定链接http://www.zillow.com/webservice/GetDeepSearchResults.htm?zws-id=<ZWSID>&address=2114+Bigelow+Ave&citystatezip=Seattle%2C+WA

相同的输出

如何对NSString进行URL编码

1 个答案: