<html>
<head>
<script>
function showUser(str,st1)
{
if (str=="" AND st1=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","http://www.tndte.com/Result/Default2.aspx?Value="+str"regul="+st,true);
xmlhttp.send();
}
</script>
</head>
<body>
<center>
<form>
Enter the Register No: <input type="text" name="reg"/><br /><br />
<input type="radio" value="K" name="s1" >K/L/R/O/N-scheme <input type="radio" value="J" name="s1" >J/C/D/G-scheme
<br /><br />
<input type="submit" value="View" name="submit" id="valuebtn" onClick="oload()" />
</form>
</center>
<br>
<div id="txtHint"><b>Person info will be listed here.</b></div>
</body>
<script type="text/javascript">
function oload(){
document.getElementById('valuebtn').onclick = function() {
var s = document.getElementById('reg').value;
var ss = document.getElementById('s1').value;
showUser(s,ss);
}
}
</script>
</html>
上述程序是为了在原始网站的帮助下自行检查结果而编写的。在ajax XMLHttpRequest的帮助下,我将值传递给函数。但它没有回应。任何人都可以帮助我。?
答案 0 :(得分:1)
答案 1 :(得分:1)
AND
不是javascript关键字。在&&
声明中使用if
。