Question

我有一个（简化的）Django模型，类似于以下内容：

models.py

# python
class Hotel(models.Model):
     name = models.Charfield()

class RoomType(models.Model):
     hotel=models.ForeignKey(Hotel, related_name="roomtypes")
     price=models.IntegerField() # really  a currency field

class Room(models.Model):
     hotel = models.ForeignKey(Hotel)
     roomType = models.ForeignKey(RoomType, related_name="rooms")

class Reservation(models.Model):
     room = models.ForeignKey(Room)
     date = models.DateField()

因此，模板所需的层次结构为Hotel->RoomType->Room，其中每个模板都已过滤。

views.py

# only get available rooms that meet the user supplied criteria in q
q = Q() # complex query building omitted
rooms = Room.objects.filter(q) 

# only get roomtypes that have rooms meeting criteria in q
roomTypesValues = rooms.values_list('roomType', flat=True)
roomTypes = RoomType.objects.filter(pk__in=list(roomTypesValues))

# only get hotels that have rooms meeting criteria in q
hotelsValues = roomTypes.values_list('hotel', flat=True)
hotels = Hotel.objects.filter(pk__in=list(hotelsValues))

c=RequestContext(request, {'hotels': hotels})

这些查询中的每一个都在某种程度上起作用。我还没弄清楚如何在模板中使用它们。

我正试图让这样的东西工作（HTML简化）：

template.html

{% for hotel in hotels %}
<h1>{{hotel.name}}</h1>

   <ul>
   {% for roomtype in hotel.roomtypes %}
     <li>
       {{roomtype.name]}, {{roomtype.price}}
       {% for room in roomtype.rooms %}
            <!-- not really needed for this -->
       {% endfor %}
     </li>
   {% endfor %}
   </ul>
{% endfor %}

如何将对象传递给模板，以便我可以采用与上述类似的方式处理它们？

Answer 1

您的第一个代码段可以简化为这一次调用：

hotels = Hotel.objects.filter(roomtype__room=<whatever your criteria are>)

您无法在模板中执行此查询，但您可以将该hotels查询集传递给模板以进行渲染。

Django中的复杂过滤

1 个答案: