我编写了一个excel互操作代码来生成Excel工作表报告。生成报告并保存在一个文件夹中。在此之后,我想下载相同的文件,并在同一个应用程序中编写了一个代码供下载。文件格式为.xlsx。我在下载时遇到以下错误。
Cannot open the file, file fotmat may be different or file may be corrected.
但如果我直接去驱动器,我可以打开同一个文件。
下载代码:
private void DownloadFile(string getpathfromappconfig, string FileName)
{
string path = @getpathfromappconfig + "\\" + FileName + ".xlsx";
System.IO.FileInfo file = new System.IO.FileInfo(path);
string Outgoingfile = FileName + ".xlsx";
if (file.Exists)
{
Response.Clear();
Response.AddHeader("Content-Disposition", "attachment; filename=" + Outgoingfile);
Response.AddHeader("Content-Length", file.Length.ToString());
Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
Response.WriteFile(file.FullName);
}
else
{
Response.Write("This file does not exist.");
}
}
有人可以帮我解决这个问题吗?
答案 0 :(得分:2)
您可以尝试使用此代码
Response.ContentType = "application/vnd.ms-excel"
替换此
Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
或者您可以尝试使用此代码
Excel.Application xlApp ;
Excel.Workbook xlWorkBook ;
Excel.Worksheet xlWorkSheet ;
object misValue = System.Reflection.Missing.Value;
xlApp = new Excel.ApplicationClass();
xlWorkBook = xlApp.Workbooks.Open("YourFile.xls", 0, true, 5, "", "", true, Microsoft.Office.Interop.Excel.XlPlatform.xlWindows, "\t", false, false, 0, true, 1, 0);
xlWorkSheet = (Excel.Worksheet)xlWorkBook.Worksheets.get_Item(1);
//your treatment ...
xlWorkBook.Close(true, misValue, misValue);
xlApp.Quit();
//Clean your objects