我试图让两个方块同时移动...... 我知道第一个动画重复到无限但我应该怎么做?
答案 0 :(得分:2)
原因是您需要等待第一个动画完成,然后再告诉方框开始下一组动画。在你的代码中,你没有给红框一个机会开始制作动画,因为黄色的一个经常这样做(有一个由animateTheBox
创建的闭包,两个框都在调用它):)
所以我将完整的函数处理程序添加到.animate()
并将animateTheBox()
调用移到那里。
答案 1 :(得分:2)
其他两个解决方案都是正确的,但请不要将您的代码列为if else条件的大量内部块的列表。请考虑以下解决方案:
$(document).ready(function(){
animateTheBox('block1',0);
animateTheBox('block2',2);
});
function animateTheBox(block,i) {
var animation = {};
var duration = 3000;
var easing = 'linear';
var done = function(){ animateTheBox(block, (i+1)%4); };
switch(i){
case 0: animation = {'left' : "-=100px"}
break;
case 1: animation = {'top' : "-=100px"}
break;
case 2: animation = {'left' : "+=100px"}
break;
case 3: animation = {'top' : "+=100px"}
break;
default: return; //This is so you can't call the function in weird ways, as before.
}
$('.' + block).animate(animation, duration, easing, done);
}
使用switch语句确定要执行的动画类型,然后只编写一次实际的动画调用。这种抽象更易于阅读,并且具有更易于维护的额外好处。您可以确保每次都以相同的方式完成动画。
修改强>
虽然从长远来看上述设计模式可能更好,但您可以使用数组轻松完成此操作:
$(document).ready(function(){
animateTheBox('block1',0);
animateTheBox('block2',2);
});
function animateTheBox(block,i) {
var animations = [
{'left' : "-=100px"}
, {'top' : "-=100px"}
, {'left' : "+=100px"}
, {'top' : "+=100px"}
];
var duration = 3000;
var easing = 'linear';
var done = function(){ animateTheBox(block, (i+1)%4); };
if ( i < 0 || i >= animations.length)
return; //Don't deal with out of bound numbers.
$('.' + block).animate(animations[i], duration, easing, done);
}
实际上,这可以使多步动画抽象变得非常简单:
$(document).ready(function(){
var block1Steps = [
{'left' : "-=100px"}
, {'top' : "-=100px"}
, {'left' : "+=100px"}
, {'top' : "+=100px"}
];
var block2Steps = [
{'left' : "+=100px"}
, {'top' : "+=100px"}
, {'left' : "-=100px"}
, {'top' : "-=100px"}
];
multiAnimate($('.block1'), block1Steps, 3000, 'linear', true);
multiAnimate($('.block2'), block2Steps, 3000, 'linear', true);
});
function multiAnimate(item, animations, duration, easing, infinite){
var i = -1;
var step = function(){
i++;
if (infinite)
i %= animations.length;
if (i >= animations.length) return;
item.animate(animations[i], duration, easing, step);
};
step();
}
然后,如果你想获得真正的Apeshit,你可以给每个动画自己的持续时间和缓和,以及BAM!你基本上为自己创建了一个任意的多步动画库。
function multiAnimate(item, animations, duration, easing, infinite){
var defaultDuration = 1000;
var defaultEasing = 'linear';
var i = -1;
var step = function(){
i++;
if (infinite)
i %= animations.length;
if (i >= animations.length) return;
item.animate(animations[i].animation
, (animations[i].duration)? animations[i].duration: defaultDuration
, (animations[i].easing)? animations[i].easing: defaultEasing
, step
);
};
step();
}
$(document).ready(function(){
var block1Steps = [
{
animation: {'left' : "-=100px"}
, duration: 3000
, easing: 'linear'
}
, {
animation: {'top' : "-=100px"}
, duration: 1000
, easing: 'swing'
}
, {
animation: {'left' : "+=100px"}
, duration: 5000
, easing: 'swing'
}
, {
animation: {'top' : "+=100px"}
, duration: 2000
, easing: 'linear'
}
];
var block2Steps = [
{
animation: {'left' : "+=100px"}
, duration: 5000
, easing: 'swing'
}
, {
animation: {'top' : "+=100px"}
, duration: 2000
, easing: 'linear'
}
, {
animation: {'left' : "-=100px"}
, duration: 3000
, easing: 'linear'
}
, {
animation: {'top' : "-=100px"}
, duration: 1000
, easing: 'swing'
}
];
multiAnimate($('.block1'), block1Steps, 3000, 'linear', true);
multiAnimate($('.block2'), block2Steps, 3000, 'linear', true);
});
答案 2 :(得分:1)
你需要使用每个动画的完成功能来开始下一个动画:
$(document).ready(function(){
animateTheBox('block1',0);
animateTheBox('block2',2);
});
function animateTheBox(block,i) {
if (i==0)
{
$('.'+block).animate({'left' : "-=100px"}, 3000, 'linear', function() {
animateTheBox(block,1);
});
}
else if (i==1)
{
$('.'+block).animate({'top' : "-=100px"}, 3000, 'linear', function() {
animateTheBox(block,2);
});
}
else if (i==2)
{
$('.'+block).animate({'left' : "+=100px"}, 3000, 'linear', function() {
animateTheBox(block,3);
});
}
else if (i==3)
{
$('.'+block).animate({'top' : "+=100px"}, 3000, 'linear', function() {
animateTheBox(block,0);
});
}
}
工作演示:http://jsfiddle.net/jfriend00/39SUN/
本着DRY的精神,这是一个更短的方式:
$(document).ready(function(){
animateTheBox('.block1',0);
animateTheBox('.block2',2);
});
function animateTheBox(block,i) {
var anims = [
{left: "-=100px"},
{top: "-=100px"},
{left: "+=100px"},
{top: "+=100px"},
];
$(block).animate(anims[i], 3000, 'linear', function() {
animateTheBox(block,(i+1) % 4);
});
}