Question

我尝试修改显示共享ID的重复行的现有查询，同时具有不同的辅助ID。

SELECT  IM.*, C.Client, U.Name, R.FrequencyUnit, R.FrequencyDuration, R.RIID
FROM    itemsMisc IM
LEFT JOIN Clients C on C.ClientID = IM.ClientID
LEFT JOIN Users U on U.UserID = IM.UserID
LEFT JOIN Recurringitem R ON (R.ClientID = C.ClientID AND IM.Rate = R.Rate AND IM.Title = R.Title)
WHERE   (IM.CID = <cfqueryparam cfsqltype="CF_SQL_INTEGER" value="#CID#">) 
  AND   (IM.Invoiced = 0)
ORDER BY IM.DateCompleted ASC;

发生的事情是，如果同一个用户制作了2个相似的重复项，则重复的行显示的是相同的IMID（来自itemsMisc），但是来自Recurringitems的RIID不同。

我在IMID上尝试了GROUP BY，发现我必须在GROUP BY中包含所有选择项，这让我无处可去。

SELECT IM.IMID, IM.UserID, IM.ClientID, IM.Rate, IM.Title, IM.CID, IM.QTY, IM.DateCompleted, C.Client, U.Name, R.FrequencyUnit, R.FrequencyDuration, R.RBID
FROM    ItemMisc IM
LEFT JOIN Clients C on C.ClientID = IM.ClientID
LEFT JOIN Users U on U.UserID = IM.UserID
LEFT JOIN Recurringitem R ON (R.ClientID = C.ClientID AND IM.Rate = R.Rate AND IM.Title = R.Title)
WHERE   (IM.CID = <cfqueryparam cfsqltype="CF_SQL_INTEGER" value="#CID#">) 
  AND   (IM.Invoiced = 0)
GROUP BY IM.IMID, IM.UserID, IM.ClientID, IM.Rate, IM.Title, IM.CID, IM.QTY, IM.DateCompleted, C.Client, U.Name, R.FrequencyUnit, R.FrequencyDuration, R.RBID
ORDER BY IM.DateCompleted ASC;

如果我能说清楚的话，请告诉我。

提前致谢

Answer 1

你有一些选择

您可以从R.RBID和select条款中删除group by
在Rate，Title，FrequencyUnit，FrequencyDuration上创建一个唯一键，这样您就不会获得“类似项目”
每个Rate，Title，FrequencyUnit，FrequencyDuration

如果它是你想要的最后一个，你可以使用row_number来获取一个且每个只有一个RBID（速率，标题，频率和频率）

WITH cte 
     AS (SELECT IM.imid, IM.userid, IM.clientid, IM.rate, 
                IM.title, IM.cid,  IM.qty, IM.datecompleted, 
                C.client, U.name, R.frequencyunit, R.frequencyduration, 
                R.rbid, 
                Row_number() 
                  OVER ( 
                    partition BY R.rate, R.title, R.frequencyunit, R.frequencyduration 
                    ORDER BY R.rbid ) rn 
         FROM   itemmisc IM 
                LEFT JOIN clients C 
                       ON C.clientid = IM.clientid 
                LEFT JOIN users U 
                       ON U.userid = IM.userid 
                LEFT JOIN recurringitem R 
                       ON ( R.clientid = C.clientid 
                            AND IM.rate = R.rate 
                            AND IM.title = R.title ) 
        WHERE   (IM.CID = <cfqueryparam cfsqltype="CF_SQL_INTEGER" value="#CID#">) 
            AND   (IM.Invoiced = 0)
         GROUP  BY IM.imid, IM.userid, IM.clientid, IM.rate, 
                   IM.title, IM.cid, IM.qty, IM.datecompleted, 
                   C.client, U.name, R.frequencyunit, R.frequencyduration, 
                   R.rbid) 
SELECT * 
FROM   cte 
WHERE  rn = 1 
ORDER  BY im.datecompleted ASC

注意：您可以通过修改partition BY

的成员来定义“类似项目”

尝试使用GROUP BY消除重复的行，使用3 LEFT JOIN

1 个答案: