Question

在下面的数组中，您会看到userId = 16。但是，当我运行foreach循环时，它会返回userId = 1。为什么它会返回1而不是16？

Array
(
    [userId] => 16
    [positionTitle] => Array
        (
            [0] => j1
            [1] => j2
        )

    [company] => Array
        (
            [0] => c1
            [1] => c2
        )

    [jobDescription] => Array
        (
            [0] => d1
            [1] => d2
        )

    [startDate] => Array
        (
            [0] => 03/01/2013
            [1] => 03/03/2013
        )

    [endDate] => Array
        (
            [0] => 03/02/2013
            [1] => 03/04/2013
        )

    [jobCity] => Array
        (
            [0] => city1
            [1] => city2
        )

    [jobState] => Array
        (
            [0] => state1
            [1] => state2
        )

)

循环代码：

foreach($updates as $key => $value){
    echo $key . " " . $value[0] . "<br/>";
}

示例输出：

userId 1
positionTitle j1
company c1
jobDescription d1
startDate 03/01/2013
endDate 03/02/2013
jobCity city1
jobState state1

Answer 1

你的问题在这里：

foreach($updates as $key => $value){
    echo $key . " " . $value[0] . "<br/>";
}

输出字符串“16”的第1个字符（第0个元素）。

将您的代码更改为此内容以获得所需的效果：

foreach($updates as $key => $value){
    if(!is_array($value))
       echo $key . " " . $value . "<br/>";
    else
       echo $key . " " . $value[0] . "<br/>";
}

为什么我的用户ID被切断了？

1 个答案: