Question

我编写了一个简单的脚本，可以找出当前在机器上运行的活动进程数，并将每个进程的路径作为字符串输出到数组中。

这是我的代码（它实际上没有合法的功能，我只是想尝试不同的东西来看看AppleScript是如何工作的）：

tell application "System Events"
  set activeProcess to number of process
  set paths to {0}
  repeat with n from 1 to activeProcess
    set last item of list paths to (file of process n as string)
  end repeat
end tell

这是我点击跑步时错误的AppleScript编辑器返回的错误：

System Events got an error: Can’t set list {0} to "Macintosh HD:System:Library:CoreServices:loginwindow.app:".

我没有错？

Answer 1

尝试：

tell application "System Events" to set myprocess to files of processes

或

set AppleScript's text item delimiters to linefeed
tell application "System Events" to set myprocess to paragraphs of (files of processes as text)
set AppleScript's text item delimiters to {""}

您可以从重复循环中构建一个列表，如下所示：

set paths to {}
tell application "System Events"
    set activeProcess to processes
    repeat with n from 1 to count activeProcess
        set end of paths to (file of item n of activeProcess as text)
    end repeat
end tell

或者像这样：

set paths to {}
tell application "System Events"
    set activeProcess to processes
    repeat with aProcess in activeProcess
        set end of paths to (file of aProcess as text)
    end repeat
end tell

在列表中存储字符串时，Applescript返回错误

1 个答案: