我有一张桌子
EmployeeID IndividualPay FamilyPay IsActive
1 200 300 true
1 100 150 false
但我想要输出如下(我想将此输出用于与其他表的内连接)
EmployeeID IndPay_IsActive IndPay_IsNotActive FamilyPay_IsActive FamilyPay_IsNotActive
1 200 100 300 150
我调查了PIVOT
,但不确定如何在我的情况下使用它。
答案 0 :(得分:24)
此类转换称为 pivot 。您没有指定正在使用的数据库,但您可以在任何系统中使用带有CASE
表达式的聚合函数:
select employeeid,
max(case when IsActive = 'true' then IndividualPay end) IndPay_IsActive,
max(case when IsActive = 'false' then IndividualPay end) IndPay_IsNotActive,
max(case when IsActive = 'true' then FamilyPay end) FamilyPay_IsActive,
max(case when IsActive = 'false' then FamilyPay end) FamilyPay_IsNotActive
from yourtable
group by employeeid
根据您的数据库,如果您有权访问PIVOT
和UNPIVOT
函数,则可以使用它们来获取结果。 UNPIVOT
函数会将IndividualPay
和FamilyPay
列转换为行。完成后,您可以使用PIVOT
函数创建四个新列:
select *
from
(
select employeeid,
case when isactive = 'true'
then col+'_IsActive'
else col+'_IsNotActive' end col,
value
from yourtable
unpivot
(
value
for col in (IndividualPay, FamilyPay)
) unpiv
) src
pivot
(
max(value)
for col in (IndividualPay_IsActive, IndividualPay_IsNotActive,
FamilyPay_IsActive, FamilyPay_IsNotActive)
) piv
两者都给出了相同的结果:
| EMPLOYEEID | INDIVIDUALPAY_ISACTIVE | INDIVIDUALPAY_ISNOTACTIVE | FAMILYPAY_ISACTIVE | FAMILYPAY_ISNOTACTIVE |
----------------------------------------------------------------------------------------------------------------
| 1 | 200 | 100 | 300 | 150 |
答案 1 :(得分:3)
Select
EmployeeID,
Active.IndividualPay As IndPay_IsActive,
Active.FamilyPay As FamilyPay_IsActive,
Inactive.IndividualPay As IndPay_IsNotActive,
Inactive.FamilyPay As FamilyPay_IsNotActive
From
PayTable Active
Join PayTable Inactive On Active.EmployeeID = Inactive.EmployeeId
And Inactive.IsActive = 'false'
Where
Active.IsActive = 'true'