Question

我的数组就像这样

(1,2,3,)
(4,5,6,)
(7,8,9,)

我想连接所有这些值，即123456789

我试过这个NSString *str5=[array componentsJoinedByString:@" "];

但我没有得到输出。

任何人都可以向我提供一些信息。

Answer 1

您的NSArray似乎有NSArray。首先循环原始NSArray并展平它，然后应用componentsJoinedByString。

创建NSMutableArray，遍历原始数组并使用每个子数组调用addObjectsFromArray:。

NSMutableArray *flattenArray = [[NSMutableArray alloc] init];
for(NSArray *array in originalArray)
{
    [flattenArray addObjectsFromArray: array];
}

NSString *str5 = [flattenArray componentsJoinedByString:@" "];

这应该有用。

Answer 2

尝试这样它给出预期的输出，但我不知道它是否是有效的方法，

NSArray *arr=[[NSArray alloc]initWithObjects:@"(1,2,3)",@"(4,5,6)", nil];
    NSString *str=[arr componentsJoinedByString:@""];
    NSCharacterSet *doNotWant = [NSCharacterSet characterSetWithCharactersInString:@",()"];
    str = [[str componentsSeparatedByCharactersInSet: doNotWant] componentsJoinedByString: @""];
    NSLog(@"%@",str);

Answer 3

尝试将此字符替换为空值的括号。

代码::

NSArray *arr = [[NSArray alloc] initWithObjects:@"(1, 2, 3, )", @"(4, 5, 6, )", @"(7, 8, 9, )", nil];

for (int i = 0; i < [arr count]; i++) {
    NSLog (@"==> %@", [or objectAtIndex:i]);
}

NSString *str5 = [arr componentsJoinedByString:@" "];
NSLog(@" ==> %@", str5);

str5 = [str5 stringByReplacingOccurrencesOfString:@"(" withString:@""];
str5 = [str5 stringByReplacingOccurrencesOfString:@" " withString:@""];
str5 = [str5 stringByReplacingOccurrencesOfString:@")" withString:@""];
str5 = [str5 stringByReplacingOccurrencesOfString:@"," withString:@""];

//Or Try this
NSCharacterSet *doNotWantChars = [NSCharacterSet characterSetWithCharactersInString:@",() "];
str5 = [[str5 componentsSeparatedByCharactersInSet: doNotWantChars] componentsJoinedByString: @""];
NSLog(@" ==> %@", str5);

NSLog(@"Output :: %@", str5);

我已经取代“（”，“）”，“”＆amp;带有“”（null）值的“，”

希望它会对你有所帮助。
谢谢。

如何通过排除括号来连接NSArray值？

3 个答案: