Question

您好我正在使用函数json_encode通过关联数组从数据库中检索数据。但是，我想问一下如何将img标记转换为字符串并将其放入关联数组中然后让json对其进行编码并将所有img标记保存为字符串时吐出所有内容？

 while($row=$result->FetchRow())
{
  $id= (float)$row['id'];
  $name = $row['name'];
  $color1 = $row['color'];
  $type1 = $row['type'];
  $to= (float)$row['to']; 
  $thumb =$row['thumb']; //image path

  $array = array(
  "adjacencies" => array( array(
  "nodeTo" => "$to",
  "nodeFrom" => "$id",
  "data" => array() )),
  "data" => array(
   "$"."color" => $color1,
   "$"."type" => $type1 ),
  "id" => $id,
  "name" => "<img src='$thumb' height='30' width='30' alt='root'/><label>$name</label> ");
}
$json = json_encode($array);
print "$json";
return $json;

Answer 1

试试这个：

$array=array();
while($row=$result->FetchRow())
{
    $id= (float)$row['id'];
    $name = $row['name'];
    $color1 = $row['color'];
    $type1 = $row['type'];
    $to= (float)$row['to']; 
    $thumb =$row['thumb']; //image path

    $array = array(
        "adjacencies" => array( array(
            "nodeTo" => "$to",
            "nodeFrom" => "$id",
            "data" => array() 
        )),
        "data" => array(
            "$"."color" => $color1,
            "$"."type" => $type1 ),
        "id" => $id,
        "name" =>htmlspecialchars("<img src='".$thumb."' height='30' width='30' alt='root'/><label>".$name."</label>")
    );
}
$json = json_encode($array);
echo $json;
return $json;

阅读http://php.net/manual/en/function.htmlspecialchars.php

Answer 2

首先，每次通过循环时都要覆盖$ array。考虑修复以下行

...
$thumb =$row['thumb']; //image path

$array = array(
"adjacencies" => array( array(
"nodeTo" => "$to",
...

到

...
$thumb =$row['thumb']; //image path

$array[] = array(
"adjacencies" => array( array(
"nodeTo" => "$to",
...

除此之外，只用一些默认变量

试用了你的代码

$id = $to = 1;
$color1 = 'green';
$type1 = 'type1';
$thumb = 'image.jpg';
$name = 'image name';
$array = array(
    "adjacencies" => array(
        array(
            "nodeTo" => $to,
            "nodeFrom" => $id,
            "data" => array()
        )
    ),
    "data" => array(
        "$"."color" => $color1,
        "$"."type" => $type1
    ),
    "id" => $id,
    "name" => "<img src='$thumb' height='30' width='30' alt='root'/><label>$name</label> "
);
echo json_encode($array);

返回给我这个JSON，这似乎是你在找什么？

{
    "adjacencies": [
        {
            "nodeTo": 1,
            "nodeFrom": 1,
            "data": []
        }
    ],
    "data": {
        "$color": "green",
        "$type": "type1"
    },
    "id": 1,
    "name": "<img src='image.jpg' height='30' width='30' alt='root'/><label>image name</label> "
}

Answer 3

使用htmlspecialchars确保转义任何有问题的字符（http://php.net/manual/en/function.htmlspecialchars.php）。除此之外，它只是字符串数据，直到您将其插入DOM。

我假设在循环的每次迭代中，您打算在数组中添加另一个元素$ array。您想在循环

之前初始化$ array变量

$array = array()

而不是

$array = array(
...
)

在循环中，执行

$array[$key] = array(
...
)

其中$ key是您要用来索引数组的键。我假设您想要使用$ id。你也可以增加一个整数并使用它。

如何将Img src转换为字符串，将其放入数组并使用json进行编码？

3 个答案: