Question

我有一个从模型中收集数据的表单。问题是如果我更新模型/数据库中的信息，它将不会在表单中显示，直到服务器重新启动。

forms.py

class RecordForm(forms.Form):
  name = forms.CharField(max_length=255)
  type_choices = []
  choices = Domain.objects.all()
  for choice in choices:
    type_choices.append( (choice.id, choice.name) )
  domain = forms.TypedChoiceField(choices=type_choices)
  type = forms.TypedChoiceField(choices=Record.type_choices)
  content = forms.CharField()
  ttl = forms.CharField()
  comment = forms.CharField()

我从Domain模型中提取数据。在网站上我有一个页面输入域信息。然后是另一个页面，它将在下拉框中列出这些域。但是，如果添加或删除任何内容，则在重新启动服务器之前，它不会显示在保管箱中。我的猜测是django只调用一次表单类。有没有办法确保在创建变量时重新运行类代码？

Answer 1

class RecordForm(forms.Form):
    name = forms.CharField(max_length=255)
    domain = forms.TypedChoiceField(choices=[])
    type = forms.TypedChoiceField(choices=...)
    content = forms.CharField()
    ttl = forms.CharField()
    comment = forms.CharField()

    def __init__(self, *args, **kwargs):
        super(RecordForm, self).__init__(*args, **kwargs)
        self.fields['type'].choices = [(c.id, c.name) for c in Domain.objects.all()]

Answer 2

每次实例化Domain时，您需要通过覆盖模型表单的RecordForm来获取__init__个对象。

class RecordForm(forms.Form):
    def __init__(self, *args, **kwargs):
        super(RecordForm, self).__init__(*args, **kwargs)
        self.type_choices = [(choice.id, choice.name,) for choice in \
            Domain.objects.all()]

    domain = forms.TypedChoiceField(choices=self.type_choices)
    ...

django - 表单字段不会在没有服务器重置的情况下更新...再次实例化一个类

2 个答案: