我希望创建一个XML,其中包含以下内容: -
<?xml version="1.0" encoding="utf-8"?>
<Groups>
<Group>
<Id>1</Id>
<GroupName>Group1</CategoryId>
<Products>
<Product>
<ProductId>1</ProductId>
<ProductName>Apples</ProductName>
</Product>
<Product>
<ProductId>2</ProductId>
<ProductName>Oranges</ProductName>
</Product>
<Product>
<ProductId>3</ProductId>
<ProductName>Lemons</ProductName>
</Product>
</Products>
<DateCreated></DateCreated>
<DateModified></DateModified>
</Group>
<Group>
<Id>2</Id>
<GroupName>Group2</CategoryId>
<Products>
<Product>
<ProductId>3</ProductId>
<ProductName>Grapes</ProductName>
</Product>
<Product>
<ProductId>4</ProductId>
<ProductName>PineApple</ProductName>
</Product>
</Products>
<DateCreated></DateCreated>
<DateModified></DateModified>
</Group>
</Groups>
从我的示例中可以看出,Product
的数量可以从1组变化到另一组。
如何创建动态XML并且以后能够读取相同的XML。
目前我创建XML的代码如下:
internal XElement ConstructGroupXML(int numberOfItems)
{
XElement xmlList = new XElement("Groups",
from a in dataModel.CreateGroupList(numberOfItems)
select new XElement("Group",
new XElement("Id", a.Id),
new XElement("GroupName", a.GroupName),
new XElement("Products",
new XElement("ProductId", a.Products[i].Id),
new XElement("ProductName", a.Products[i].ProductName),
new XElement("CategoryId", a.Products[i].Category.Id),
new XElement("CategoryName", a.Products[i].Category.CategoryName),
new XElement("SubCategoryId", a.Products[i].SubCategory.Id),
new XElement("SubCategoryName", a.Products[i].SubCategory.SubCategoryName),
new XElement("DateCreated", a.DateCreated),
new XElement("DateModified", a.DateModified)
)
);
return xmlList;
}
CreateGroupList
方法返回一个对象,其中包含嵌入在这些组中的组和产品列表,因此对于每个组,我希望在产品列表中循环并生成XML。
答案 0 :(得分:1)
好的,我找到了解决方案:
from o in a.Products
select new XElement("Products",
new XAttribute("ProductId", o.Id),
new XElement("ProductName", o.ProductName),
new XElement("CategoryId", o.Category.Id),
new XElement("CategoryName", o.Category.CategoryName),
new XElement("SubCategoryId", o.SubCategory.Id),
new XElement("SubCategoryName", o.SubCategory.SubCategoryName),
现在我只需要了解如何阅读此XML