我正在制作一个性别相关的名字字典,所以我有一个主表可以说:
**name_dict a**
name gender
=======================
jhon male
jane female
anna female
和一个源数据表,它有“重复”,我的意思是,同名,具有不同的性别,如下所示:
**name_source b**
name gender
=======================
cameron male
cameron female
anna female
travis male
我想将这两个表与这些条件合并
我如何创建合并以获得此结果?
name gender
----------------
jhon male
jane female
anna female
travis male
我非常感谢你的帮助和建议!
编辑---------------------------------------------- -------------------------- 所以,这就是我用灵感创造的东西
merge into name_dictionary x using(
select a.name,a.gender from name_source a, (select name,count(1) from name_source group by name having count(1)>1 order by count(1)) b
where a.name=b.name
) y
on (x.name=y.name)
when not matched then
insert (name,gender)
values (y.name,y.gender)
然后我说,让我们对我们的朋友Thomas Tschernich的消化进行测试,因为我用过:
insert into name_dictionary
select name,gender
from name_source t1
where
(t1.name, t1.gender) not in (
select name, gender from name_dictionary
)
and
(t1.name, t1.gender) not in (
select t2.name, t2.gender
from name_source t2
join name_source t3 on (t2.name = t3.name and t2.gender != t3.gender)
);
然后互相攻击并得到:
QUERY EXEC TIME FINAL ROWS PLAN DATA
merge 2 secs 96,070 MERGE STATEMENT ALL_ROWS Cost: 253 Bytes: 46,752 Cardinality: 974
c-Insert killed (31m) ¿? INSERT STATEMENT ALL_ROWS Cost: 24,656,135 Bytes: 1,051,700 Cardinality: 105,170
这是我使用的表格的信息:
Table Initial Rows Observations
name_dictionary 3,097 The ones already inserted
name_source 101,205 The ones i want to filter and add to the name_dictionary
(无法正确格式化,希望其可读性) 无论如何,我希望你能详细说明它是对还是我错过了什么,非常感谢!!!
---新发现 如果我在合并中删除订单,则成本上升到298;
答案 0 :(得分:1)
使用两个单独的插入可能比合并更容易。 首先,插入表a中的所有条目,如下所示:
insert into name_new select * from name_dict
然后,为您的第二个表执行条件插入,如下所示:
insert into name_new
select *
from name_source t1
where
(t1.name, t1.gender) not in (
select name, gender from name_new
)
and
(t1.name, t1.gender) not in (
select t2.name, t2.gender
from name_source t2
join name_source t3 on (t2.name = t3.name and t2.gender != t3.gender)
)
第一个where
部分对anna-case进行排序,第二个部分将对两个性别的重复进行排序。