Question

我是matlab的新手并试图编写生命游戏。但是我在制作neigbors的总和方面遇到了一些困难。每个单元格的值都可以是0或1.我正在尝试使用一个计数器（就像在Python中，我唯一熟悉的程序），但这似乎不起作用。问题是必须对所有细胞起作用，边界细胞也是如此。如果我有每个单元格的值（因此它将介于0到8之间），我必须实现规则。但我也不知道这是否正确。请帮忙！我变得绝望了！

TIME = 50;


pulsar;

life = {};  % create list 'life'
life{1} = X;  % add seed to life

numrows = size(X,1); % calculate number of rows
numcolumns = size (X,2);  % calculate number of columns

current = X;            % make seed the first current(matrix you're starting off with in each step)

for i = 0:TIME;    % determine amount of times the loop will run 

for row = 1:numrows;              % for each row
    for column = 1:numcolumns;    % for each column

 if column + 1 ~= numcolumns + 1
 east_of_row = column + 1;  % define how to count the cell right of target cell
 end
 if column - 1 ~= 0
 west_of_row = column - 1; % define how to count the cell left of target cell    
 end
 if row - 1 ~= 0
 north_of_column = row - 1; % define how to count the cell north of target cell    
 end
 if row + 1 ~= numrows + 1
 south_of_column = row + 1;
 end

  neighbors = 0                               % start counter 'neighbors' with 0

            if current(row,east_of_row) == 1;              % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                  % add 1 to neighbors
            end
            if current(row,west_of_row) == 1;              % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                  % add 1 to neighbors
            end
            if current(north_of_column,column) == 1;       % if neighboring cell has a value of 1    
                neighbors = neighbors + 1;                                  % add 1 to neighbors
            end
            if current(south_of_column,column) == 1;       % if neighboring cell has a value of 1    
                neighbors = neighbors + 1;                                   % add 1 to neighbors
            end
            if current(south_of_column,east_of_row) == 1;  % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                   % add 1 to neighbors
            end
            if current(north_of_column,east_of_row) == 1;  % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                  % add 1 to neighbors
            end
            if current(north_of_column,west_of_row) == 1;  % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                  % add 1 to neighbors
            end
            if current(south_of_column,west_of_row) == 1;  % if neighboring cell has a value of 1
                neighbors = neighbors + 1;                                   % add 1 to neighbors     
            end


        % rules of the game:

    if current(row,column) == 1;              % in case a target cell has a value of 1:

        if neighbors < 2                           % if the number of neighbors is smaller than 2
            nextnext(row,column) = 0;                   % value of target cell gets 0 in nextnext
        end
        if neighbors == 2                      % if the number of neighbors is 2 or 3
            nextnext(row,column) = 1;                   % value of target cell stays 1 in nextnext
        end
        if  neighbors == 3
            nextnext(row,column) = 1;
        end
        if neighbors > 3                        % if the number of neigbors is higher than 3
            nextnext(row,column) = 0;                   % value of target cell gets 0 in nextnext
        end
    end
    if current (row,column) == 0           % in case a target cell has a value of 0:

        if neighbors == 3                          % if the number of neighbors is 3
            nextnext(row,column) = 1;                   % value of target cell gets 1 in nextnext
        end
        if neighbors ~= 3                       % if the number of neigbors isn't 3
            nextnext(row,column) = 0;                  % value of target cell stays 0 in nextnext
        end
end
    end
end


current = nextnext;       % make nextnext matrix the current matrix for the next step 
%life{TIME} = nextnext;    % add matrix to list 'life

end



show(life);

Answer 1

您可以使用conv2计算此值，如下所示：

%First create some example matrix 
%  (this is a 5 x 5 matrix with 30% 1's, 70% 0's
x = full(ceil(sprand(5,5,0.3)))

%Create your convolution kernal
%    This will add up all the values in the 8 elements surrounding the
%    central element
k = [1 1 1; 1 0 1; 1 1 1];  

%Now do the copnvulution (using the 'same' argument to select an output
%the same size as the input.)
counts = conv2(x,k,'same')

每次都会创建一个略有不同的示例。但是对于上面代码的一次执行，我得到以下结果：

x =
     0     1     0     1     0
     0     1     0     1     0
     0     0     1     1     0
     0     1     0     1     0
     0     0     0     0     0

counts =
     2     1     4     1     2
     2     2     6     3     3
     2     3     5     3     3
     1     1     4     2     2
     1     1     2     1     1

如何在matlab中总结neigburs的价值？

1 个答案: