我有一张这样的表:
$sql = "CREATE TABLE dramaStudio
(
rowId varchar(1) not null,
columnId int not null,
status int,
firstName varchar(15) not null,
lastName varchar(15) not null,
updatedby varchar(10),
PRIMARY KEY (rowId, columnId)
)";
在我网站的主页上,我希望用户能够看到是否有任何免费座位而无需进入座位计划。几乎只是说“免费席位:”后跟一个数字。 我在伪代码中的逻辑是:
$j=0
select * from dramaStudio
for every status == 0
$j+1
echo $j
非常感谢任何帮助。
答案 0 :(得分:1)
只需对状态为0的所有字段执行COUNT
SELECT COUNT(*) FROM dramaStudio WHERE status = '0'
答案 1 :(得分:1)
如果空位:
,假设状态= 0SELECT COUNT(*) AS freeseats FROM dramaStudio WHERE status=0
完整示例,来自php手册:
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");
/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$query = "SELECT COUNT(*) AS freeseats FROM dramaStudio WHERE status=0";
$result = mysqli_query($link, $query);
/* associative array */
$row = mysqli_fetch_array($result, MYSQLI_ASSOC);
echo $row['freeseats']; // this is an integer
/* free result set */
mysqli_free_result($result);
/* close connection */
mysqli_close($link);
?>
答案 2 :(得分:1)
参见示例代码
$con = mysql_connect("localhost", "peter", "abc123");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
$db_selected = mysql_select_db("test_db",$con);
$sql = "SELECT * from Person";
$result = mysql_query($sql,$con);
while ($property = mysql_fetch_field($result))
{
echo "Field name: " . $property->name . "<br />";
echo "Table name: " . $property->table . "<br />";
echo "Default value: " . $property->def . "<br />";
echo "Max length: " . $property->max_length . "<br />";
echo "Not NULL: " . $property->not_null . "<br />";
echo "Primary Key: " . $property->primary_key . "<br />";
echo "Unique Key: " . $property->unique_key . "<br />";
echo "Mutliple Key: " . $property->multiple_key . "<br />";
echo "Numeric Field: " . $property->numeric . "<br />";
echo "BLOB: " . $property->blob . "<br />";
echo "Field Type: " . $property->type . "<br />";
echo "Unsigned: " . $property->unsigned . "<br />";
echo "Zero-filled: " . $property->zerofill . "<br /><br />";
}
mysql_close($con);
答案 3 :(得分:1)
你正在存放填充的座位?为了找出空,你必须指定colomn和行的数量。
如果填充的空座位可以在表格中区分。 你可以这样做,
$query = "select * from dramaStudio where status = 0";
$result_Set = mysql_query($query);
while($row = mysql_fetch_object($result_set)){
echo $row->rowId .',', $row->columnId;
echo '</br>';
}