Question

这是我做的 -

grid_len = input("Enter Grid Length: ") //Assuming grid_length to be 3
s = []
while True:
    s.append(input())
    if len(s) == int(grid_len)**2: //grid_length^2 will be 9
        print(s)
        break

当输入在第一个循环中为例如1时，在第二个循环中为2，在第三个循环中为3，依此类推至9;它会创建一个这样的列表：

['1','2','3','4','5','6','7','8','9']

但我想要这样的事情：

[[1,2,3],[4,5,6],[7,8,9]]

Answer 1

基于列表理解的版本。

s = [[input("Enter number: ") for _ in range(grid_len)] for _ in range(grid_len)]
print s

注意：两个正斜杠“//”不是有效的python注释标识符

Answer 2

我从这个问题找到的东西：How do you split a list into evenly sized chunks?

>>> mylist = [1,2,3,4,5,6,7,8,9]
>>> def chunks(l, n):
...    return [l[i:i+n] for i in range(0, len(l), n)]
>>> chunks(mylist,3)
[[1, 2, 3], [4, 5, 6], [7, 8, 9]]

集成到您的代码中：

def chunks(l, n):
    return [l[i:i+n] for i in range(0, len(l), n)]
grid_len = input("Enter Grid Length: ")
s = []
while True:
    s.append(int(input())) # Notice I put int() around input()
    if len(s) == int(grid_len)**2:
        s = chunks(s,grid_len)
        print(s)
        break

编辑：更改了块中的第二个参数以匹配grid_len。现在这不仅适用于3。

Answer 3

这是我的代码：

grid_len = input("Enter Grid Length: ")
s = []
for i in range(grid_len):         #looping to append rows
    s.append([])                  #append a new row
    for j in range(grid_len):     #looping to append cells
        s[-1].append(input())     #append a new cell to the last row, or you can also append to `i`th row

Answer 4

尝试一下：

arr = [list(map(int, input().split())) for i in range(int(input()))]

Answer 5

您应该为每个grid_length元素创建一个新的子列表：

grid_len = int(input("Enter Grid Length: "))
s = []
for _ in range(grid_length):
    sub_list = []
    for _ in range(grid_length):
        sub_list.append(input())
    s.append(sub_list)
print(s)

请注意，通常，每次必须在对象上顺序迭代或者您知道重复循环的次数时，应使用for。 while通常更好地处理难以考虑迭代次数或迭代迭代次数的“奇怪”条件。

Answer 6

使用嵌套列表推导：

>>> grid_len = input("Enter Grid Length: ")
Enter Grid Length: 4
>>> incrementer = iter(xrange(1, grid_len ** 2 + 1))
>>> s = [[next(incrementer) for x in xrange(grid_len)] for y in xrange(grid_len)]
>>> print s
[[1, 2, 3, 4], [5, 6, 7, 8], [9, 10, 11, 12], [13, 14, 15, 16]]

Answer 7

试试这个：

x = [[int(input()) for c in range(grid_len)] for r in range(grid_len)]

Answer 8

我遇到了您的问题，非常简单的解决方法是

grid_length = int(input())
s = []
for i in range(grid_length):
     b = input().split()
     for i in range(len(b)):
         b[i] = int(b[i]) #for converting into integers
     s.append(b)
print(s)

Answer 9

试试这个：

grid_len = int(input()) #just one input
grid = [[input(),input(),input()] for _ in range(grid_len)] #grid_len * 3 inputs
print(grid)

列表列表：如何从用户输入中列出列表？

9 个答案: